Chapter 11, Problem 4CT

To determine

To Find: The area.

Answer to Problem 4CT

  $225\pi m^2$

Explanation of Solution

Given: A circle with $circumference=30\pi m$ .

Given: $circumference=30\pi m$

  $\begin{array}{l}C=2\pi r\\ 30\pi =2\pi r\\ r=15m\\ now\\ A=\pi r^2\\ $ A=\pi {(15)}^2$A=225\pi m^2\end{array}$