Chapter 11.2, Problem 10WE

To determine

To Find: The area.

Answer to Problem 10WE

  $A=60sq.unit$

Explanation of Solution

Given: An isosceles triangle with base $10$ and perimeter $36$ .

Base: $10$

Perimeter= $36$

  $36-10=26$

Since isosceles triangles has two sides equal.

  $\frac{26}{2}=13$

Sides: $10,13,13$

  

Using Pythagoras theorem

  $\begin{array}{l}{H}^2=P^2+B^2\\ {13}^2=P^2+5^2\\ P^2=169-25\\ P^2=144\\ P=12\end{array}$

Area of isosceles triangle.

  $\begin{array}{l}A=\frac{2bh}{2}\\ A=(5)(12)\\ A=60sq.unit\end{array}$

Hence, $A=60sq.unit$