Chapter 11.2, Problem 33STP

To determine

To find: Value of $x$

Answer to Problem 33STP

Subtract $105$ from $180$

  $x^0={75}^0$

Explanation of Solution

Given information:

Angles are ${60}^0$ and ${45}^0$

We know

Sum of angles of a triangle is ${180}^0$

Using that

We get

  ${60}^0+{45}^0+x^0={180}^0$

On solving

We get

  $\begin{array}{l}{60}^0+{45}^0+x^0={180}^0\\ \Rightarrow {105}^0+x^0={180}^0\\ \Rightarrow x^0={180}^0-{105}^0\end{array}$

Therefore,

We can get value of $x$ by Subtract $105$ from $180$

  $\Rightarrow x^0={75}^0$