Chapter 11.2, Problem 2GP

To determine

To find: Value of $x$ in each triangle.

Answer to Problem 2GP

  $x={60}^0$

Explanation of Solution

Given information:

Two angles of a triangle are ${60}^0$ and ${60}^0$

Given

Two angles of a triangle are ${60}^0$ and ${60}^0$

We know sum of angles of a triangle is ${180}^0$

Using that

We get

  $x^0+{60}^0+{60}^0={180}^0$

On solving

  $\begin{array}{l}{x}^0+{60}^0+{60}^0={180}^0\\ \Rightarrow x^0+{120}^0={180}^0\\ \Rightarrow x^0={180}^0-{120}^0\\ \Rightarrow x^0={60}^0\end{array}$

Therefore,

  $x={60}^0$

As all the three angles are less than ${90}^0$ and equal

So, it is an Equilateral triangle