Chapter 11.2, Problem 20IP

To determine

To find: The value of $x$ .

Answer to Problem 20IP

  $x={32}^0$

Explanation of Solution

Given information:

Exterior angle $={160}^0$

Opposite interior angles are $2x^0$ and $3x^0$

Given

Exterior angle $={160}^0$

Opposite interior angles are $2x^0$ and $3x^0$

We know exterior angle is equal to sum of opposite interior angles

Using that

We get

  $2x+3x={160}^0$

On solving

  $\begin{array}{l}2x+3x={160}^0\\ \Rightarrow 5x={160}^0\\ \Rightarrow x=\frac{{160}^0}{5}\\ \Rightarrow x={32}^0\end{array}$

Therefore,

  $x={32}^0$