Chapter 11.1, Problem 41STP

To determine

To find:The value of $x$

Answer to Problem 41STP

  $x^0={30}^0$

Explanation of Solution

Given information:

  $4x^0$ and ${120}^0$ are congruent angles.

  $4x^0$ and ${120}^0$ are congruent angles.

It means

  $\begin{array}{l}4x^0={120}^0\\ \Rightarrow x^0=\frac{{120}^0}{4}\\ \Rightarrow x^0={30}^0\end{array}$

Therefore,

  $x^0={30}^0$