Chapter 11.1, Problem 42STP

To determine

To find:The value of $x$

Answer to Problem 42STP

  $x^0={148}^0$

Explanation of Solution

Given information:

One of the angle is ${32}^0$

From the given figure

We can say that

  ${32}^0$ and $x^0$ forms a straight line

It means they are supplementary angles

So, Sum of their measure is ${180}^0$

  $x^0+{32}^0={180}^0$

On solving

We get

  $\begin{array}{l}\Rightarrow x^0+{32}^0={180}^0\\ \Rightarrow x^0={180}^0-{32}^0\\ \Rightarrow x^0={148}^0\end{array}$

Therefore,

  $x^0={148}^0$