Concept explainers
To draw: The conclusion and justify it.
Explanation of Solution
Given:
The table is:
Use Facebook | Main Campus | Common wealth |
Several times a month or less | 55 | 76 |
At least once a week | 215 | 157 |
At least once a day | 640 | 394 |
Total Facebook users | 910 | 627 |
The P -value using calculator is 0.000059.
Calculation:
The null and alternative hypotheses are:
The P -value is less than the significance level, the null hypothesis can be rejected.
At 5% significance level, there is enough evidence to state that there is a difference in the distribution of users in both the schools.
Chapter 11 Solutions
The Practice of Statistics for AP - 4th Edition
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