Concept explainers
a.
To check: If the expected counts are large enough for using the chi-square distribution. Also, compute the degree of freedom
a.
Answer to Problem 5E
The degree of freedom is 3.
Explanation of Solution
Given:
The proportions are 0.52, 0.27, 0.13 and 0.08
Total counts are 150
The test statistic is 6.5988.
Formula used:
The formula to compute the degree of freedom is:
Degree of freedom = Number of categories - 1
The expected counts could be computed as:
From above calculations, it is clear that the expected counts are above 5.
The degree of freedom is:
Degree of freedom is 4-1 = 3
b.
To construct: The figure that shows the p -value
b.
Explanation of Solution
Graph:
The figure showing P -value is constructed as:
c.
To find: The P -value using table and calculator.
c.
Answer to Problem 5E
The P -value is 0.086.
Explanation of Solution
Calculation:
The P -value at 2 degree of freedom using table is:
Now, the P -value using Ti-83 calculator is:
Thus, the P -value is 0.086.
d.
To draw: The conclusion about the claim of the company
d.
Answer to Problem 5E
There is insufficient evidence to reject the claim of the company.
Explanation of Solution
Calculation:
The P -value is above the significance level. The null hypothesis cannot be rejected. Thus, there is insufficient evidence to reject the claim about the distribution of the company for its deluxe mixed nuts.
Chapter 11 Solutions
The Practice of Statistics for AP - 4th Edition
Additional Math Textbook Solutions
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Elementary Statistics: Picturing the World (6th Edition)
Elementary Statistics
Statistical Reasoning for Everyday Life (5th Edition)
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Elementary Statistics: Picturing the World (7th Edition)
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