Chapter 11, Problem 7PT

To determine

To find: The degree of freedom.

Answer to Problem 7PT

The degree of freedom is 2.

Explanation of Solution

Given:

The table is:

	Leukaemia	Lymphoma	Other cancers
HCC	52	10	17
LCC	84	21	31

Formula used:

The formula to compute the degree of freedom is:

  $\text{Degree of freedom =}\left(\text{Number of rows-1}\right)\left(\text{Number of columns-1}\right)$

Calculation:

Number of rows = 3

Number of columns = 2

The degree of freedom is calculated as:

  $\begin{array}{c}\text{Degree of freedom =}\left(\text{Number of rows-1}\right)\left(\text{Number of columns-1}\right)\\ =\left(3-1\right)\left(2-1\right)\\ =2\end{array}$

The correct option is (b).