
Concept explainers
a.
To find: The test that is to be used in the provided case.
a.

Answer to Problem 52E
Chi-square test of homogeneity.
Explanation of Solution
Given:
The output is:
Here, two-way table has been computed for the one qualitative variable of two sample. Thus, chi-square test of homogeneity should be used here.
b.
To state: The appropriate null and alternative hypotheses for the provided test.
b.

Explanation of Solution
Calculation:
The appropriate null and alternative hypotheses for the provided test could be written as:
c.
To check: If the required conditions to conduct the test are met or not.
c.

Explanation of Solution
Here, in this case following conditions are following:
- Sample is chosen random.
- All the expected counts are above 5.
- The size of the sample is 10% smaller than the population.
Thus, it could be said that the required conditions are fulfilled.
d.
To interpret: The P -value and draw the conclusion.
d.

Explanation of Solution
If no relationship exists between the variables then the likelihood of having same or extreme sample is 0.01%
Conclusion:
The p -value < 0.05. The null hypothesis is rejected. Thus, at 5% significance level there is sufficient evidence to reject the claim that there is an association between the two variables.
Chapter 11 Solutions
The Practice of Statistics for AP - 4th Edition
Additional Math Textbook Solutions
A Problem Solving Approach To Mathematics For Elementary School Teachers (13th Edition)
Algebra and Trigonometry (6th Edition)
A First Course in Probability (10th Edition)
Elementary Statistics: Picturing the World (7th Edition)
Calculus: Early Transcendentals (2nd Edition)
College Algebra (7th Edition)
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