Concept explainers
To draw: The conclusion that could be drawn using the provided information.
Explanation of Solution
Given:
The table is:
Leukaemia | Lymphoma | Other cancers | |
HCC | 52 | 10 | 17 |
LCC | 84 | 21 | 31 |
The test statistic is 0.435.4
Calculation:
The hypotheses are:
The degree of freedom is calculated as:
The p-value using chi-square table at 2 degree of freedom is 0.1955.
The p -value is above significance level. The null hypothesis does not get rejected. There is enough evidence to be in favor of claim at 5% significance level.
The correct option is (d).
Chapter 11 Solutions
The Practice of Statistics for AP - 4th Edition
Additional Math Textbook Solutions
Essentials of Statistics, Books a la Carte Edition (5th Edition)
Statistics: The Art and Science of Learning from Data (4th Edition)
Intro Stats, Books a la Carte Edition (5th Edition)
Elementary Statistics (13th Edition)
An Introduction to Mathematical Statistics and Its Applications (6th Edition)
Essentials of Statistics (6th Edition)
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