Introductory Chemistry: Concepts and Critical Thinking (8th Edition)
Introductory Chemistry: Concepts and Critical Thinking (8th Edition)
8th Edition
ISBN: 9780134421377
Author: Charles H Corwin
Publisher: PEARSON
Question
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Chapter 11, Problem 77E
Interpretation Introduction

(a)

Interpretation:

The water of hydration for the compound SrCl2XH2O is to be calculated which contains 18.5% water. The chemical formula of the compound SrCl2XH2O is to be stated.

Concept introduction:

The water of crystallization is the number of water molecules present in crystal compounds. The water of crystallization is also known as water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.

Expert Solution
Check Mark

Answer to Problem 77E

The water of hydration for the compound SrCl2XH2O is 2. The chemical formula of compound is SrCl22H2O.

Explanation of Solution

The compound SrCl2XH2O contains 18.5% water. Therefore, 100 g of the compound will have 18.5 g of water in it.

The mass of SrCl2 unit in 100 g of the compound is calculated as shown below.

mSrCl2=100 g18.5 g=81.5 g

The molar mass of water is 18.02 g/mol.

The molar mass of SrCl2 is 158.53  g/mol.

The number of moles of a substance is given by the expression as shown below.

n=mM …(1)

Where,

m is the mass of the substance.

M is the molar mass of the substance.

Substitute the values of mass and molar mass of water in the equation (1).

n=18.5 g18.02 g/mol=1.027 mol

Substitute the values of mass and molar mass of SrCl2 in the equation (1).

n=81.5 g158.53  g/mol=0.514 mol

The molar ratio of SrCl2:H2O can be obtained by dividing the number of moles with the lowest number of mole that is 0.514 mol.

SrCl2:H2O=0.514 mol0.514 mol:1.027 mol0.514 molSrCl2:H2O=1:1.998SrCl2:H2O1:2

Therefore, the water of hydration for the compound SrCl2XH2O is 2 and the chemical formula of the compound is SrCl22H2O.

Conclusion

The water of hydration for the compound SrCl22H2O is calculated as 2. The chemical formula of compound is SrCl22H2O.

Interpretation Introduction

(b)

Interpretation:

The water of hydration for the compound Sr(NO3)2XH2O is to be calculated which contains 33.8% water. The chemical formula of the compound Sr(NO3)2XH2O is to be stated.

Concept introduction:

The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as the water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.

Expert Solution
Check Mark

Answer to Problem 77E

The water of hydration for the compound Sr(NO3)2:H2O is 6 and the chemical formula of the compound is Sr(NO3)26H2O.

Explanation of Solution

The compound Sr(NO3)2XH2O contains 33.8% water. Therefore, 100 g of the compound will have 33.8 g of water in it.

The mass of Sr(NO3)2 unit in 100 g of the compound is calculated as shown below.

mSr(NO3)2=100 g33.8 g=66.2 g

The molar mass of water is 18.02 g/mol.

The molar mass of Sr(NO3)2 is 211.6298  g/mol.

The number of moles of a substance is given by the expression as shown below.

n=mM …(1)

Where,

m is the mass of the substance.

M is the molar mass of the substance.

Substitute the values of mass and molar mass of water in the equation (1).

n=33.8 g18.02 g/mol=1.876 mol

Substitute the values of mass and molar mass of Sr(NO3)2 in the equation (1).

n=66.2 g211.6298 g/mol=0.313 mol

The molar ratio of Sr(NO3)2:H2O can be obtained by dividing the number of moles with the lowest number of mole that is 0.313 mol.

Sr(NO3)2:H2O=0.313 mol0.313 mol:1.876 mol0.313 molSr(NO3)2:H2O=1:5.994Sr(NO3)2:H2O1:6

Therefore, the water of hydration for the compound Sr(NO3)2:H2O is 6 and the chemcial formula of the compound is Sr(NO3)26H2O.

Conclusion

The water of hydration for the compound Sr(NO3)26H2O is calculated as 6. The chemcial formula of the compound is Sr(NO3)26H2O.

Interpretation Introduction

(c)

Interpretation:

The water of hydration for the compound Ca(NO3)2XH2O is to be calculated which contains 30.5% water. The chemical formula of the compound Ca(NO3)2XH2O is to be stated.

Concept introduction:

The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as the water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.

Expert Solution
Check Mark

Answer to Problem 77E

The water of hydration for the compound Ca(NO3)2XH2O is 4 and the chemical formula of the compound is Ca(NO3)24H2O.

Explanation of Solution

The compound Ca(NO3)2XH2O contains 30.5% water. Therefore, 100 g of the compound will have 30.5 g of water in it.

The mass of Ca(NO3)2 unit in 100 g of the compound is calculated as shown below.

mCa(NO3)2=100 g30.5 g=69.5 g

The molar mass of water is 18.02 g/mol.

The molar mass of Ca(NO3)2 is 164.0878 g/mol.

The number of moles of a substance is given by the expression as shown below.

n=mM …(1)

Where,

m is the mass of the substance.

M is the molar mass of the substance.

Substitute the values of mass and molar mass of water in the equation (1).

n=30.5 g18.02 g/mol=1.693 mol

Substitute the values of mass and molar mass of Ca(NO3)2 in the equation (1).

n=69.5 g164.0878 g/mol=0.4235 mol

The molar ratio of Ca(NO3)2:H2O can be obtained by dividing the number of moles with the lowest number of mole that is 0.4235 mol.

Ca(NO3)2:H2O=0.4235 mol0.4235 mol:1.693 mol0.4235 molCa(NO3)2:H2O=1:3.9976Ca(NO3)2:H2O1:4

Therefore, the water of hydration for the compound Ca(NO3)2XH2O is 4 and the chemical formula of the compound is Ca(NO3)24H2O.

Conclusion

The water of hydration for the compound Ca(NO3)24H2O is 4. The chemical formula of the compound is Ca(NO3)24H2O.

Interpretation Introduction

(d)

Interpretation:

The water of hydration for the compound Na2B4O7XH2O is to be calculated which contains 30.9% water. The chemical formula of the compound Na2B4O7XH2O is to be stated.

Concept introduction:

The water of crystallization is the number of water molecules present in crystals compounds. The water of crystallization is also known as the water of hydration. The water molecules present in the crystal helps the crystal to impart color. These water molecules can be easily removed from the crystal by heating them.

Expert Solution
Check Mark

Answer to Problem 77E

The water of hydration for the compound Na2B4O7XH2O is 5 and the chemical formula of the compound is Na2B4O75H2O.

Explanation of Solution

The compound Na2B4O7XH2O contains 30.9% water. Therefore, 100 g of the compound will have 30.9 g of water in it.

The mass of Na2B4O7 unit in 100 g of the compound is calculated as shown below.

mNa2B4O7=100 g30.9 g=69.1 g

The molar mass of water is 18.02 g/mol.

The molar mass of Na2B4O7 is 201.22  g/mol.

The number of moles of a substance is given by the expression as shown below.

n=mM …(1)

Where,

m is the mass of the substance.

M is the molar mass of the substance.

Substitute the values of mass and molar mass of water in the equation (1).

n=30.9 g18.02 g/mol=1.715 mol

Substitute the values of mass and molar mass of Na2B4O7 water in the equation (1).

n=69.1 g201.22  g/mol=0.343 mol

The molar ratio of Na2B4O7:H2O can be obtained by dividing the number of moles with the lowest number of mole that is 0.343 mol.

Na2B4O7:H2O=0.343 mol0.343 mol:1.715 mol0.343 molNa2B4O7:H2O=1:5

Therefore, the water of hydration for the compound Na2B4O7XH2O is 5 and the chemical formula of the compound is Na2B4O75H2O.

Conclusion

The water of hydration for the compound Na2B4O75H2O is 5. The chemical formula of the compound is Na2B4O75H2O.

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Chapter 11 Solutions

Introductory Chemistry: Concepts and Critical Thinking (8th Edition)

Ch. 11 - Prob. 3KTCh. 11 - Prob. 4KTCh. 11 - Prob. 5KTCh. 11 - Prob. 6KTCh. 11 - Prob. 7KTCh. 11 - Prob. 8KTCh. 11 - Prob. 9KTCh. 11 - Prob. 10KTCh. 11 - Prob. 11KTCh. 11 - Prob. 12KTCh. 11 - Prob. 13KTCh. 11 - Prob. 14KTCh. 11 - Prob. 15KTCh. 11 - Prob. 16KTCh. 11 - Prob. 17KTCh. 11 - Prob. 18KTCh. 11 - Prob. 19KTCh. 11 - Prob. 20KTCh. 11 - Prob. 21KTCh. 11 - Prob. 22KTCh. 11 - Prob. 23KTCh. 11 - Prob. 24KTCh. 11 - Prob. 25KTCh. 11 - Prob. 26KTCh. 11 - Prob. 1ECh. 11 - Prob. 2ECh. 11 - Prob. 3ECh. 11 - Prob. 4ECh. 11 - Prob. 5ECh. 11 - Prob. 6ECh. 11 - Prob. 7ECh. 11 - Prob. 8ECh. 11 - Prob. 9ECh. 11 - Prob. 10ECh. 11 - Prob. 11ECh. 11 - Prob. 12ECh. 11 - Prob. 13ECh. 11 - Prob. 14ECh. 11 - Prob. 15ECh. 11 - Prob. 16ECh. 11 - Prob. 17ECh. 11 - Prob. 18ECh. 11 - Prob. 19ECh. 11 - Prob. 20ECh. 11 - Prob. 21ECh. 11 - Prob. 22ECh. 11 - Prob. 23ECh. 11 - Prob. 24ECh. 11 - Prob. 25ECh. 11 - Prob. 26ECh. 11 - Prob. 27ECh. 11 - Prob. 28ECh. 11 - Prob. 29ECh. 11 - Prob. 30ECh. 11 - Prob. 31ECh. 11 - Prob. 32ECh. 11 - Prob. 33ECh. 11 - Prob. 34ECh. 11 - Prob. 35ECh. 11 - Prob. 36ECh. 11 - Prob. 37ECh. 11 - Prob. 38ECh. 11 - Prob. 39ECh. 11 - Prob. 40ECh. 11 - Prob. 41ECh. 11 - Prob. 42ECh. 11 - Prob. 43ECh. 11 - Prob. 44ECh. 11 - Prob. 45ECh. 11 - Prob. 46ECh. 11 - Prob. 47ECh. 11 - Prob. 48ECh. 11 - Prob. 49ECh. 11 - Prob. 50ECh. 11 - Prob. 51ECh. 11 - Prob. 52ECh. 11 - Prob. 53ECh. 11 - Prob. 54ECh. 11 - Prob. 55ECh. 11 - Prob. 56ECh. 11 - Prob. 57ECh. 11 - Prob. 58ECh. 11 - Prob. 59ECh. 11 - Prob. 60ECh. 11 - Prob. 61ECh. 11 - Prob. 62ECh. 11 - Prob. 63ECh. 11 - Prob. 64ECh. 11 - Prob. 65ECh. 11 - Prob. 66ECh. 11 - Prob. 67ECh. 11 - Prob. 68ECh. 11 - Prob. 69ECh. 11 - Prob. 70ECh. 11 - Prob. 71ECh. 11 - Prob. 72ECh. 11 - Prob. 73ECh. 11 - Prob. 74ECh. 11 - Prob. 75ECh. 11 - Prob. 76ECh. 11 - Prob. 77ECh. 11 - Prob. 78ECh. 11 - Prob. 79ECh. 11 - Prob. 80ECh. 11 - Prob. 81ECh. 11 - Prob. 82ECh. 11 - Prob. 83ECh. 11 - Prob. 84ECh. 11 - Prob. 85ECh. 11 - Prob. 86ECh. 11 - Prob. 87ECh. 11 - Prob. 88ECh. 11 - Prob. 1STCh. 11 - Prob. 2STCh. 11 - Prob. 3STCh. 11 - Prob. 4STCh. 11 - Prob. 5STCh. 11 - Prob. 6STCh. 11 - Prob. 7STCh. 11 - Prob. 8STCh. 11 - Prob. 9STCh. 11 - Prob. 10STCh. 11 - Prob. 11STCh. 11 - Prob. 12STCh. 11 - Prob. 13STCh. 11 - Prob. 14ST
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