The initial rate for a reaction is equal to the slope of the tangent line at t ≈ 0 in a plot of [A] versus time. From calculus, initial rate = − d [ A ] d t . Therefore. the differential rate law for a reaction is Rate = − d [ A ] d t = k [ A ] n . Assuming you have some calculus in your background, derive the zero-, first-, and second-order integrated rate laws using the differential rate law.
The initial rate for a reaction is equal to the slope of the tangent line at t ≈ 0 in a plot of [A] versus time. From calculus, initial rate = − d [ A ] d t . Therefore. the differential rate law for a reaction is Rate = − d [ A ] d t = k [ A ] n . Assuming you have some calculus in your background, derive the zero-, first-, and second-order integrated rate laws using the differential rate law.
Solution Summary: The author explains that the initial rate for a reaction is equal to the slope of the tangent line at tapprox 0. The zero-, first- and second-order integrated rate
The initial rate for a reaction is equal to the slope of the tangent line at t ≈ 0 in a plot of [A] versus time. From calculus, initial rate =
−
d
[
A
]
d
t
. Therefore. the differential rate law for a reaction is Rate =
−
d
[
A
]
d
t
=
k
[
A
]
n
.
Assuming you have some calculus in your background, derive the zero-, first-, and second-order integrated rate laws using the differential rate law.
Definition Definition Study of the speed of chemical reactions and other factors that affect the rate of reaction. It also extends toward the mechanism involved in the reaction.
Indicate the order of basicity of primary, secondary and tertiary amines.
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Classify each of the following molecules as aromatic, antiaromatic, or nonaromatic.
Cl
Z-
N
O aromatic
O antiaromatic
O nonaromatic
O aromatic
O antiaromatic
O nonaromatic
O aromatic
○ antiaromatic
nonaromatic
Please help me answer this question. I don't understand how or even if this can happen in a single transformation. Please provide a detailed explanation and a drawing showing how it can happen in a single transformation.
Add the necessary reagents and reaction conditions above and below the arrow in this organic reaction. If the products can't be made from the reactant with a single transformation, check the box under the drawing area instead.
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