Chapter 11, Problem 38E

(a)

Interpretation Introduction

Interpretation: The general reaction, initial concentration of reactant and slope of straight line graph of $\ln \left[\text{A}\right]$ versus time is given. The answers are to be given for each option.

Concept introduction: The change observed in the concentration of a reactant or a product per unit time is known as the rate of the particular reaction. The differential rate law provides the rate of a reaction at specific reaction concentrations.

The half-life of the first order reaction is calculated using the formula,

$t_{\frac{\text{1}}{\text{2}}}=\frac{\text{0}\text{.693}}{k}$

(b)

Interpretation Introduction

Interpretation: The general reaction, initial concentration of reactant and slope of straight line graph of $\ln \left[\text{A}\right]$ versus time is given. The answers are to be given for each option.

Concept introduction: The change observed in the concentration of a reactant or a product per unit time is known as the rate of the particular reaction. The differential rate law provides the rate of a reaction at specific reaction concentrations.

The half-life of the first order reaction is calculated using the formula,

$t_{\frac{\text{1}}{\text{2}}}=\frac{\text{0}\text{.693}}{k}$

(c)

Interpretation Introduction

Interpretation: The general reaction, initial concentration of reactant and slope of straight line graph of $\ln \left[\text{A}\right]$ versus time is given. The answers are to be given for each option.

Concept introduction: The change observed in the concentration of a reactant or a product per unit time is known as the rate of the particular reaction. The differential rate law provides the rate of a reaction at specific reaction concentrations.

The half-life of the first order reaction is calculated using the formula,

$t_{\frac{\text{1}}{\text{2}}}=\frac{\text{0}\text{.693}}{k}$