ACHIEVE/CHEMICAL PRINCIPLES ACCESS 1TERM
7th Edition
ISBN: 9781319399849
Author: ATKINS
Publisher: MAC HIGHER
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Chapter 11, Problem 11.53E
Interpretation Introduction
Interpretation:
The disadvantages of using coal as a fuel have to be given.
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Please draw the structure in the box that is consistent with all the spectral data and
alphabetically label all of the equivalent protons in the structure (Ha, Hb, Hc....) in order to assign all
the proton NMR peaks. The integrations are computer generated and approximate the number of
equivalent protons. Molecular formula: C13H1802
14
13
12
11
10
11 (ppm)
Structure with assigned H peaks
2.08
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Firefly luciferin exhibits three rings. Identify which of the rings are aromatic. Identify which lone pairs are involved in establishing aromaticity. The lone pairs are labeled A-D below.
Chapter 11 Solutions
ACHIEVE/CHEMICAL PRINCIPLES ACCESS 1TERM
Ch. 11 - Prob. 11A.1ASTCh. 11 - Prob. 11A.1BSTCh. 11 - Prob. 11A.2ASTCh. 11 - Prob. 11A.2BSTCh. 11 - Prob. 11A.3ASTCh. 11 - Prob. 11A.3BSTCh. 11 - Prob. 11A.4ASTCh. 11 - Prob. 11A.4BSTCh. 11 - Prob. 11A.5ASTCh. 11 - Prob. 11A.5BST
Ch. 11 - Prob. 11A.6ASTCh. 11 - Prob. 11A.6BSTCh. 11 - Prob. 11A.1ECh. 11 - Prob. 11A.2ECh. 11 - Prob. 11A.3ECh. 11 - Prob. 11A.4ECh. 11 - Prob. 11A.5ECh. 11 - Prob. 11A.6ECh. 11 - Prob. 11A.7ECh. 11 - Prob. 11A.8ECh. 11 - Prob. 11A.9ECh. 11 - Prob. 11A.10ECh. 11 - Prob. 11A.11ECh. 11 - Prob. 11A.12ECh. 11 - Prob. 11A.13ECh. 11 - Prob. 11A.14ECh. 11 - Prob. 11A.15ECh. 11 - Prob. 11A.16ECh. 11 - Prob. 11A.17ECh. 11 - Prob. 11A.18ECh. 11 - Prob. 11A.19ECh. 11 - Prob. 11A.20ECh. 11 - Prob. 11A.21ECh. 11 - Prob. 11A.22ECh. 11 - Prob. 11A.23ECh. 11 - Prob. 11A.24ECh. 11 - Prob. 11A.25ECh. 11 - Prob. 11A.26ECh. 11 - Prob. 11A.27ECh. 11 - Prob. 11A.28ECh. 11 - Prob. 11B.1ASTCh. 11 - Prob. 11B.1BSTCh. 11 - Prob. 11B.1ECh. 11 - Prob. 11B.3ECh. 11 - Prob. 11B.4ECh. 11 - Prob. 11B.5ECh. 11 - Prob. 11B.6ECh. 11 - Prob. 11B.7ECh. 11 - Prob. 11B.8ECh. 11 - Prob. 11C.1ASTCh. 11 - Prob. 11C.1BSTCh. 11 - Prob. 11C.1ECh. 11 - Prob. 11C.2ECh. 11 - Prob. 11C.3ECh. 11 - Prob. 11C.4ECh. 11 - Prob. 11C.5ECh. 11 - Prob. 11C.6ECh. 11 - Prob. 11C.7ECh. 11 - Prob. 11C.8ECh. 11 - Prob. 11C.9ECh. 11 - Prob. 11C.10ECh. 11 - Prob. 11C.11ECh. 11 - Prob. 11C.12ECh. 11 - Prob. 11C.13ECh. 11 - Prob. 11C.14ECh. 11 - Prob. 11D.1ASTCh. 11 - Prob. 11D.1BSTCh. 11 - Prob. 11D.2ASTCh. 11 - Prob. 11D.2BSTCh. 11 - Prob. 11D.3ASTCh. 11 - Prob. 11D.3BSTCh. 11 - Prob. 11D.1ECh. 11 - Prob. 11D.2ECh. 11 - Prob. 11D.3ECh. 11 - Prob. 11D.4ECh. 11 - Prob. 11D.5ECh. 11 - Prob. 11D.6ECh. 11 - Prob. 11D.7ECh. 11 - Prob. 11D.8ECh. 11 - Prob. 11D.9ECh. 11 - Prob. 11D.10ECh. 11 - Prob. 11D.11ECh. 11 - Prob. 11D.12ECh. 11 - Prob. 11D.13ECh. 11 - Prob. 11D.14ECh. 11 - Prob. 11D.15ECh. 11 - Prob. 11D.16ECh. 11 - Prob. 11D.17ECh. 11 - Prob. 11D.18ECh. 11 - Prob. 11D.19ECh. 11 - Prob. 11D.20ECh. 11 - Prob. 11D.21ECh. 11 - Prob. 11D.22ECh. 11 - Prob. 11D.23ECh. 11 - Prob. 11D.24ECh. 11 - Prob. 11D.25ECh. 11 - Prob. 11D.26ECh. 11 - Prob. 11D.27ECh. 11 - Prob. 11D.28ECh. 11 - Prob. 11D.29ECh. 11 - Prob. 11D.30ECh. 11 - Prob. 11D.31ECh. 11 - Prob. 11D.32ECh. 11 - Prob. 11D.33ECh. 11 - Prob. 11D.34ECh. 11 - Prob. 11D.35ECh. 11 - Prob. 11D.36ECh. 11 - Prob. 11E.1ASTCh. 11 - Prob. 11E.1BSTCh. 11 - Prob. 11E.2ASTCh. 11 - Prob. 11E.2BSTCh. 11 - Prob. 11E.1ECh. 11 - Prob. 11E.3ECh. 11 - Prob. 11E.4ECh. 11 - Prob. 11E.5ECh. 11 - Prob. 11E.7ECh. 11 - Prob. 11E.8ECh. 11 - Prob. 11E.9ECh. 11 - Prob. 11E.10ECh. 11 - Prob. 11E.11ECh. 11 - Prob. 11E.12ECh. 11 - Prob. 11E.13ECh. 11 - Prob. 11E.14ECh. 11 - Prob. 11E.15ECh. 11 - Prob. 11E.16ECh. 11 - Prob. 11E.17ECh. 11 - Prob. 11E.18ECh. 11 - Prob. 11E.19ECh. 11 - Prob. 11E.20ECh. 11 - Prob. 11E.21ECh. 11 - Prob. 11E.22ECh. 11 - Prob. 11E.23ECh. 11 - Prob. 11E.24ECh. 11 - Prob. 11E.25ECh. 11 - Prob. 11E.26ECh. 11 - Prob. 11E.27ECh. 11 - Prob. 11E.28ECh. 11 - Prob. 11.1ECh. 11 - Prob. 11.2ECh. 11 - Prob. 11.3ECh. 11 - Prob. 11.4ECh. 11 - Prob. 11.5ECh. 11 - Prob. 11.6ECh. 11 - Prob. 11.7ECh. 11 - Prob. 11.8ECh. 11 - Prob. 11.9ECh. 11 - Prob. 11.10ECh. 11 - Prob. 11.11ECh. 11 - Prob. 11.12ECh. 11 - Prob. 11.13ECh. 11 - Prob. 11.14ECh. 11 - Prob. 11.15ECh. 11 - Prob. 11.16ECh. 11 - Prob. 11.17ECh. 11 - Prob. 11.18ECh. 11 - Prob. 11.19ECh. 11 - Prob. 11.20ECh. 11 - Prob. 11.21ECh. 11 - Prob. 11.23ECh. 11 - Prob. 11.24ECh. 11 - Prob. 11.25ECh. 11 - Prob. 11.26ECh. 11 - Prob. 11.27ECh. 11 - Prob. 11.28ECh. 11 - Prob. 11.29ECh. 11 - Prob. 11.30ECh. 11 - Prob. 11.31ECh. 11 - Prob. 11.32ECh. 11 - Prob. 11.33ECh. 11 - Prob. 11.34ECh. 11 - Prob. 11.35ECh. 11 - Prob. 11.36ECh. 11 - Prob. 11.37ECh. 11 - Prob. 11.38ECh. 11 - Prob. 11.41ECh. 11 - Prob. 11.42ECh. 11 - Prob. 11.43ECh. 11 - Prob. 11.44ECh. 11 - Prob. 11.45ECh. 11 - Prob. 11.47ECh. 11 - Prob. 11.49ECh. 11 - Prob. 11.50ECh. 11 - Prob. 11.51ECh. 11 - Prob. 11.52ECh. 11 - Prob. 11.53ECh. 11 - Prob. 11.54ECh. 11 - Prob. 11.55ECh. 11 - Prob. 11.56ECh. 11 - Prob. 11.57E
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- A 0.10 M solution of acetic acid (CH3COOH, Ka = 1.8 x 10^-5) is titrated with a 0.0250 M solution of magnesium hydroxide (Mg(OH)2). If 10.0 mL of the acid solution is titrated with 10.0 mL of the base solution, what is the pH of the resulting solution?arrow_forwardGiven a complex reaction with rate equation v = k1[A] + k2[A]2, what is the overall reaction order?arrow_forwardPlease draw the structure in the box that is consistent with all the spectral data and alphabetically label all of the equivalent protons in the structure (Ha, Hb, Hc....) in order to assign all the proton NMR peaks. The integrations are computer generated and approximate the number of equivalent protons. Molecular formula: C13H1802 14 13 12 11 10 11 (ppm) Structure with assigned H peaks 2.08 3.13arrow_forward
- CHEMICAL KINETICS. One of the approximation methods for solving the rate equation is the steady-state approximation method. Explain what it consists of.arrow_forwardCHEMICAL KINETICS. One of the approximation methods for solving the rate equation is the limiting or determining step approximation method. Explain what it consists of.arrow_forwardCHEMICAL KINETICS. Indicate the approximation methods for solving the rate equation.arrow_forward
- TRANSMITTANCE เบบ Please identify the one structure below that is consistent with the 'H NMR and IR spectra shown and draw its complete structure in the box below with the protons alphabetically labeled as shown in the NMR spectrum and label the IR bands, including sp³C-H and sp2C-H stretch, indicated by the arrows. D 4000 OH LOH H₂C CH3 OH H₂C OCH3 CH3 OH 3000 2000 1500 HAVENUMBERI-11 1000 LOCH3 Draw your structure below and label its equivalent protons according to the peak labeling that is used in the NMR spectrum in order to assign the peaks. Integrals indicate number of equivalent protons. Splitting patterns are: s=singlet, d=doublet, m-multiplet 8 3Hb s m 1Hd s 3Hf m 2Hcd 2Had 1He 鄙视 m 7 7 6 5 4 3 22 500 T 1 0arrow_forwardRelative Transmittance 0.995 0.99 0.985 0.98 Please draw the structure that is consistent with all the spectral data below in the box and alphabetically label the equivalent protons in the structure (Ha, Hb, Hc ....) in order to assign all the proton NMR peaks. Label the absorption bands in the IR spectrum indicated by the arrows. INFRARED SPECTRUM 1 0.975 3000 2000 Wavenumber (cm-1) 1000 Structure with assigned H peaks 1 3 180 160 140 120 100 f1 (ppm) 80 60 40 20 0 C-13 NMR note that there are 4 peaks between 120-140ppm Integral values equal the number of equivalent protons 10.0 9.0 8.0 7.0 6.0 5.0 4.0 3.0 2.0 1.0 0.0 fl (ppm)arrow_forwardCalculate the pH of 0.0025 M phenol.arrow_forward
- In the following reaction, the OH- acts as which of these? NO2-(aq) + H2O(l) ⇌ OH-(aq) + HNO2(aq)arrow_forwardUsing spectra attached, can the unknown be predicted? Draw the predicition. Please explain and provide steps. Molecular focrmula:C16H13ClOarrow_forwardCalculate the percent ionization for 0.0025 M phenol. Use the assumption to find [H3O+] first. K = 1.0 x 10-10arrow_forward
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