Concept explainers
(a)
Interpretation:
The condensed formula of
Concept Introduction:
Condensed structural formula: Condensed structural formula shows the arrangement of atoms in grouped form.
(a)
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Answer to Problem 11A.11E
The condensed formula of
Explanation of Solution
The given compound is,
The parent chain of the compound is pentane. One methyl group is present in the carbon third position and a double bond is found in carbon first position. Hence, the systematic name of the compound is
(b)
Interpretation:
The condensed formula of
Concept Introduction:
Refer to part (a).
(b)
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Answer to Problem 11A.11E
The condensed formula of
Explanation of Solution
The given compound is,
The parent chain of the compound is heptane. One ethyl group is present in the carbon fourth position and two methyl groups are present in carbon third position. Hence, the systematic name of the compound is
(c)
Interpretation:
The condensed formula of
Concept Introduction:
Refer to part (a).
(c)
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Answer to Problem 11A.11E
The condensed formula of
Explanation of Solution
The given compound is,
The parent chain of the compound is hexane. Two methyl groups are present in carbon fifth position and a triple bond is seen at the carbon first position. Hence, the systematic name of the compound is
(d)
Interpretation:
The condensed formula of
Concept Introduction:
Refer to part (a).
(d)
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Answer to Problem 11A.11E
The condensed formula of
Explanation of Solution
The given compound is,
The parent chain of the compound is pentane. One ethyl group is present in the carbon third position and two methyl groups are present in carbon second and fourth position respectively.
Hence, the systematic name of the compound is
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Chapter 11 Solutions
ACHIEVE/CHEMICAL PRINCIPLES ACCESS 1TERM
- Experiment: Each team will be provided with 5g of a mixture of acetanilide and salicylic acid. You will divide it into three 1.5 g portions in separate 125 mL Erlenmeyer flasks savıng some for melting point analysis. Dissolve the mixture in each flask in ~60mL of DI water by heating to boiling on a hotplate. Take the flasks off the hotplate once you have a clear solution and let them stand on the bench top for 5 mins and then allow them to cool as described below. Sample A-Let the first sample cool slowly to room temperature by letting it stand on your lab bench, with occasional stirring to promote crystallization. Sample B-Cool the second sample 1n a tap-water bath to 10-15 °C Sample C-Cool the third sample in an ice-bath to 0-2 °C Results: weight after recrystalization and melting point temp. A=0.624g,102-115° B=0.765g, 80-105° C=1.135g, 77-108 What is the percent yield of A,B, and C.arrow_forwardRel. Intensity Q 1. Which one of the following is true of the compound whose mass spectrum is shown here? Explain how you decided. 100 a) It contains chlorine. b) It contains bromine. c) It contains neither chlorine nor bromine. 80- 60- 40- 20- 0.0 0.0 TT 40 80 120 160 m/z 2. Using the Table of IR Absorptions how could you distinguish between these two compounds in the IR? What absorbance would one compound have that the other compound does not? HO CIarrow_forwardIllustrate reaction mechanisms of alkenes with water in the presence of H2SO4, detailing each step of the process. Please show steps of processing. Please do both, I will thumb up for sure #1 #3arrow_forward
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- Introductory Chemistry: An Active Learning Approa...ChemistryISBN:9781305079250Author:Mark S. Cracolice, Ed PetersPublisher:Cengage Learning
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