(a) Interpretation: How to synthesize the given compound from an alkyne is to be described. Concept introduction: The carbon-carbon triple bond in terminal alkynes is electron rich and thus undergoes electrophilic addition reaction with a strong Bronsted acid such as hydrogen halide. Addition of two equivalents of hydrogen halide to a terminal alkyne produces a geminal dihalide, in which both the halide atoms are on the same carbon atom. The regioselectivity is in accordance with the Markovnikov’s rule. The hydrogen halide adds twice to generate the geminal dihalide. If hydrogen chloride is used as a reagent, the reaction goes through vinylic carbocation intermediate as the chlorine atom will stabilize the positive charge on the carbon atom through resonance. The alkyne must be symmetric to avoid producing a mixture of isomers.

Question

Want to see the full answer?

Answer 1

Question

Chapter 11, Problem 11.14P

Interpretation Introduction

(a)

Interpretation:

How to synthesize the given compound from an alkyne is to be described.

Concept introduction:

The carbon-carbon triple bond in terminal alkynes is electron rich and thus undergoes electrophilic addition reaction with a strong Bronsted acid such as hydrogen halide. Addition of two equivalents of hydrogen halide to a terminal alkyne produces a geminal dihalide, in which both the halide atoms are on the same carbon atom. The regioselectivity is in accordance with the Markovnikov’s rule. The hydrogen halide adds twice to generate the geminal dihalide. If hydrogen chloride is used as a reagent, the reaction goes through vinylic carbocation intermediate as the chlorine atom will stabilize the positive charge on the carbon atom through resonance. The alkyne must be symmetric to avoid producing a mixture of isomers.

Interpretation Introduction

(b)

Interpretation:

How to synthesize the given compound from an alkyne is to be described.

Concept introduction:

The carbon-carbon triple bond in terminal alkynes is electron rich and thus undergoes electrophilic addition reaction with a strong Bronsted acid such as hydrogen halide. Addition of two equivalents of hydrogen halide to a terminal alkyne produces a geminal dihalide, in which both the halide atoms are on the same carbon atom. The regioselectivity is in accordance with the Markovnikov’s rule. The hydrogen halide adds twice to generate the geminal dihalide. If hydrogen bromide is used as a reagent, the reaction goes through formation of a pi complex with an alkyne. This pi complex is stabilized by the attraction between electron rich triple bond and electron poor proton of the acid. The alkyne must be symmetric to avoid producing a mixture of isomers. An unsymmetric alkyne produces a mixture of isomers.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Question 9 ㅇ SN2 O E1 O E2 OSN1 CI MeOH 오~ Is this an example of an SN1, SN2, E1, or E2 reaction?

b,c,e ex

Show how to convert compounds; b,c,e

Answer 2

Question

Chapter 11, Problem 11.14P

Interpretation Introduction

(a)

Interpretation:

How to synthesize the given compound from an alkyne is to be described.

Concept introduction:

The carbon-carbon triple bond in terminal alkynes is electron rich and thus undergoes electrophilic addition reaction with a strong Bronsted acid such as hydrogen halide. Addition of two equivalents of hydrogen halide to a terminal alkyne produces a geminal dihalide, in which both the halide atoms are on the same carbon atom. The regioselectivity is in accordance with the Markovnikov’s rule. The hydrogen halide adds twice to generate the geminal dihalide. If hydrogen chloride is used as a reagent, the reaction goes through vinylic carbocation intermediate as the chlorine atom will stabilize the positive charge on the carbon atom through resonance. The alkyne must be symmetric to avoid producing a mixture of isomers.

Interpretation Introduction

(b)

Interpretation:

How to synthesize the given compound from an alkyne is to be described.

Concept introduction:

The carbon-carbon triple bond in terminal alkynes is electron rich and thus undergoes electrophilic addition reaction with a strong Bronsted acid such as hydrogen halide. Addition of two equivalents of hydrogen halide to a terminal alkyne produces a geminal dihalide, in which both the halide atoms are on the same carbon atom. The regioselectivity is in accordance with the Markovnikov’s rule. The hydrogen halide adds twice to generate the geminal dihalide. If hydrogen bromide is used as a reagent, the reaction goes through formation of a pi complex with an alkyne. This pi complex is stabilized by the attraction between electron rich triple bond and electron poor proton of the acid. The alkyne must be symmetric to avoid producing a mixture of isomers. An unsymmetric alkyne produces a mixture of isomers.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 11, Problem 11.14P

Interpretation Introduction

(a)

Interpretation:

How to synthesize the given compound from an alkyne is to be described.

Concept introduction:

The carbon-carbon triple bond in terminal alkynes is electron rich and thus undergoes electrophilic addition reaction with a strong Bronsted acid such as hydrogen halide. Addition of two equivalents of hydrogen halide to a terminal alkyne produces a geminal dihalide, in which both the halide atoms are on the same carbon atom. The regioselectivity is in accordance with the Markovnikov’s rule. The hydrogen halide adds twice to generate the geminal dihalide. If hydrogen chloride is used as a reagent, the reaction goes through vinylic carbocation intermediate as the chlorine atom will stabilize the positive charge on the carbon atom through resonance. The alkyne must be symmetric to avoid producing a mixture of isomers.

Interpretation Introduction

(b)

Interpretation:

How to synthesize the given compound from an alkyne is to be described.

Concept introduction:

The carbon-carbon triple bond in terminal alkynes is electron rich and thus undergoes electrophilic addition reaction with a strong Bronsted acid such as hydrogen halide. Addition of two equivalents of hydrogen halide to a terminal alkyne produces a geminal dihalide, in which both the halide atoms are on the same carbon atom. The regioselectivity is in accordance with the Markovnikov’s rule. The hydrogen halide adds twice to generate the geminal dihalide. If hydrogen bromide is used as a reagent, the reaction goes through formation of a pi complex with an alkyne. This pi complex is stabilized by the attraction between electron rich triple bond and electron poor proton of the acid. The alkyne must be symmetric to avoid producing a mixture of isomers. An unsymmetric alkyne produces a mixture of isomers.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 11, Problem 11.14P

Interpretation Introduction

(a)

Interpretation:

How to synthesize the given compound from an alkyne is to be described.

Concept introduction:

The carbon-carbon triple bond in terminal alkynes is electron rich and thus undergoes electrophilic addition reaction with a strong Bronsted acid such as hydrogen halide. Addition of two equivalents of hydrogen halide to a terminal alkyne produces a geminal dihalide, in which both the halide atoms are on the same carbon atom. The regioselectivity is in accordance with the Markovnikov’s rule. The hydrogen halide adds twice to generate the geminal dihalide. If hydrogen chloride is used as a reagent, the reaction goes through vinylic carbocation intermediate as the chlorine atom will stabilize the positive charge on the carbon atom through resonance. The alkyne must be symmetric to avoid producing a mixture of isomers.

Interpretation Introduction

(b)

Interpretation:

How to synthesize the given compound from an alkyne is to be described.

Concept introduction:

The carbon-carbon triple bond in terminal alkynes is electron rich and thus undergoes electrophilic addition reaction with a strong Bronsted acid such as hydrogen halide. Addition of two equivalents of hydrogen halide to a terminal alkyne produces a geminal dihalide, in which both the halide atoms are on the same carbon atom. The regioselectivity is in accordance with the Markovnikov’s rule. The hydrogen halide adds twice to generate the geminal dihalide. If hydrogen bromide is used as a reagent, the reaction goes through formation of a pi complex with an alkyne. This pi complex is stabilized by the attraction between electron rich triple bond and electron poor proton of the acid. The alkyne must be symmetric to avoid producing a mixture of isomers. An unsymmetric alkyne produces a mixture of isomers.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 11, Problem 11.14P

Interpretation Introduction

(a)

Interpretation:

How to synthesize the given compound from an alkyne is to be described.

Concept introduction:

The carbon-carbon triple bond in terminal alkynes is electron rich and thus undergoes electrophilic addition reaction with a strong Bronsted acid such as hydrogen halide. Addition of two equivalents of hydrogen halide to a terminal alkyne produces a geminal dihalide, in which both the halide atoms are on the same carbon atom. The regioselectivity is in accordance with the Markovnikov’s rule. The hydrogen halide adds twice to generate the geminal dihalide. If hydrogen chloride is used as a reagent, the reaction goes through vinylic carbocation intermediate as the chlorine atom will stabilize the positive charge on the carbon atom through resonance. The alkyne must be symmetric to avoid producing a mixture of isomers.

Interpretation Introduction

(b)

Interpretation:

How to synthesize the given compound from an alkyne is to be described.

Concept introduction:

The carbon-carbon triple bond in terminal alkynes is electron rich and thus undergoes electrophilic addition reaction with a strong Bronsted acid such as hydrogen halide. Addition of two equivalents of hydrogen halide to a terminal alkyne produces a geminal dihalide, in which both the halide atoms are on the same carbon atom. The regioselectivity is in accordance with the Markovnikov’s rule. The hydrogen halide adds twice to generate the geminal dihalide. If hydrogen bromide is used as a reagent, the reaction goes through formation of a pi complex with an alkyne. This pi complex is stabilized by the attraction between electron rich triple bond and electron poor proton of the acid. The alkyne must be symmetric to avoid producing a mixture of isomers. An unsymmetric alkyne produces a mixture of isomers.

Answer 6

Chapter 11, Problem 11.14P

Interpretation Introduction

(a)

Interpretation:

How to synthesize the given compound from an alkyne is to be described.

Concept introduction:

The carbon-carbon triple bond in terminal alkynes is electron rich and thus undergoes electrophilic addition reaction with a strong Bronsted acid such as hydrogen halide. Addition of two equivalents of hydrogen halide to a terminal alkyne produces a geminal dihalide, in which both the halide atoms are on the same carbon atom. The regioselectivity is in accordance with the Markovnikov’s rule. The hydrogen halide adds twice to generate the geminal dihalide. If hydrogen chloride is used as a reagent, the reaction goes through vinylic carbocation intermediate as the chlorine atom will stabilize the positive charge on the carbon atom through resonance. The alkyne must be symmetric to avoid producing a mixture of isomers.

Answer 7

Chapter 11, Problem 11.14P

Interpretation Introduction

(a)

Interpretation:

How to synthesize the given compound from an alkyne is to be described.

Concept introduction:

The carbon-carbon triple bond in terminal alkynes is electron rich and thus undergoes electrophilic addition reaction with a strong Bronsted acid such as hydrogen halide. Addition of two equivalents of hydrogen halide to a terminal alkyne produces a geminal dihalide, in which both the halide atoms are on the same carbon atom. The regioselectivity is in accordance with the Markovnikov’s rule. The hydrogen halide adds twice to generate the geminal dihalide. If hydrogen chloride is used as a reagent, the reaction goes through vinylic carbocation intermediate as the chlorine atom will stabilize the positive charge on the carbon atom through resonance. The alkyne must be symmetric to avoid producing a mixture of isomers.

Answer 8

Interpretation Introduction

(b)

Interpretation:

How to synthesize the given compound from an alkyne is to be described.

Concept introduction:

The carbon-carbon triple bond in terminal alkynes is electron rich and thus undergoes electrophilic addition reaction with a strong Bronsted acid such as hydrogen halide. Addition of two equivalents of hydrogen halide to a terminal alkyne produces a geminal dihalide, in which both the halide atoms are on the same carbon atom. The regioselectivity is in accordance with the Markovnikov’s rule. The hydrogen halide adds twice to generate the geminal dihalide. If hydrogen bromide is used as a reagent, the reaction goes through formation of a pi complex with an alkyne. This pi complex is stabilized by the attraction between electron rich triple bond and electron poor proton of the acid. The alkyne must be symmetric to avoid producing a mixture of isomers. An unsymmetric alkyne produces a mixture of isomers.

Answer 9

Interpretation Introduction

(b)

Interpretation:

How to synthesize the given compound from an alkyne is to be described.

Concept introduction:

The carbon-carbon triple bond in terminal alkynes is electron rich and thus undergoes electrophilic addition reaction with a strong Bronsted acid such as hydrogen halide. Addition of two equivalents of hydrogen halide to a terminal alkyne produces a geminal dihalide, in which both the halide atoms are on the same carbon atom. The regioselectivity is in accordance with the Markovnikov’s rule. The hydrogen halide adds twice to generate the geminal dihalide. If hydrogen bromide is used as a reagent, the reaction goes through formation of a pi complex with an alkyne. This pi complex is stabilized by the attraction between electron rich triple bond and electron poor proton of the acid. The alkyne must be symmetric to avoid producing a mixture of isomers. An unsymmetric alkyne produces a mixture of isomers.

Answer 10

Expert Solution & Answer

Answer 11

Expert Solution & Answer

Answer 12

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 13

Ch. 11 - Prob. 11.1P Ch. 11 - Prob. 11.2P Ch. 11 - Prob. 11.3P Ch. 11 - Prob. 11.4P Ch. 11 - Prob. 11.5P Ch. 11 - Prob. 11.6P Ch. 11 - Prob. 11.7P Ch. 11 - Prob. 11.8P Ch. 11 - Prob. 11.9P Ch. 11 - Prob. 11.10P

Solution Summary: The author explains how to synthesize the given compound from an alkyne.

Concept explainers

Videos

Want to see the full answer?

Chapter 11 Solutions