Physics: Principles with Applications
Physics: Principles with Applications
6th Edition
ISBN: 9780130606204
Author: Douglas C. Giancoli
Publisher: Prentice Hall
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Chapter 10, Problem 63GP

(a)

To determine

To calculate: The height of the bottle.

(a)

Expert Solution
Check Mark

Answer to Problem 63GP

The height is 0.75m .

Explanation of Solution

Given:

Pressure is , P1=55mm-Hg

Density of the fluid, ρ=1.00g/cm3=103kg/m3 .

Formula used:

The pressure at the particular height is given as,

  P=ρgh

Where, g is acceleration due to gravity, h is the height and ρ is the density.

Calculation:

Now substitute the given values in the above formula and so, the height is,

  P=ρghh=Pρg=55mmHg(103Kg/m3)×(9.8)=55×133Nm2(103kg/m3)×(9.8)=0.75m

Conclusion:

The height is 0.75m .

(b)

To determine

To calculate: The height of the bottle.

(b)

Expert Solution
Check Mark

Answer to Problem 63GP

The height h1' is 0.65m .

Explanation of Solution

Given:

The pressure is, P2=650mm-H2O

Density of the fluid, ρ=1.00g/cm3=103kg/m3

Formula used:

The pressure at the particular height is given as,

  P=ρgh

Where, g is acceleration due to gravity, h is the height and ρ is the density.

Calculation:

Now substitute the given values in the above formula and so, the height is,

  P=ρghh=Pρg=650×9.81Nm2(103kg/m3)×(9.8)=0.65m

Conclusion:

The height h1' is 0.65m .

(c)

To determine

To calculate: The height of the bottle.

(c)

Expert Solution
Check Mark

Answer to Problem 63GP

The height where the bottle should be placed is 0.24 m.

Explanation of Solution

Given:

The height of the opening of the tank is h1 and the height of the liquid surface is h2 . Initially, the tank is at the rest. Assume, v20

Calculation:

For the case, where the pressure is 18mm-Hg above the atmospheric pressure,

  P3=18mm-Hg=1.8cm-Hg=1.8m×13.6g

Now use this value of pressure in the given formula is,

  P=ρghh=Pρg=1.8m×13.6×9.8(103kg/m3)×(9.8)=24.48×103cm=0.24m

Conclusion:

The height is 0.24 m.

Chapter 10 Solutions

Physics: Principles with Applications

Ch. 10 - Prob. 11QCh. 10 - Prob. 12QCh. 10 - Prob. 13QCh. 10 - Prob. 14QCh. 10 - Prob. 15QCh. 10 - Prob. 16QCh. 10 - Prob. 17QCh. 10 - Prob. 18QCh. 10 - Prob. 19QCh. 10 - Prob. 20QCh. 10 - Prob. 21QCh. 10 - Prob. 22QCh. 10 - Prob. 23QCh. 10 - Prob. 24QCh. 10 - Prob. 1PCh. 10 - Prob. 2PCh. 10 - Prob. 3PCh. 10 - Prob. 4PCh. 10 - Prob. 5PCh. 10 - Prob. 6PCh. 10 - Prob. 7PCh. 10 - Prob. 8PCh. 10 - Prob. 9PCh. 10 - Prob. 10PCh. 10 - Prob. 11PCh. 10 - Prob. 12PCh. 10 - Prob. 13PCh. 10 - Prob. 14PCh. 10 - Prob. 15PCh. 10 - Prob. 16PCh. 10 - Prob. 17PCh. 10 - Prob. 18PCh. 10 - Prob. 19PCh. 10 - Prob. 20PCh. 10 - Prob. 21PCh. 10 - Prob. 22PCh. 10 - Prob. 23PCh. 10 - Prob. 24PCh. 10 - Prob. 25PCh. 10 - Prob. 26PCh. 10 - Prob. 27PCh. 10 - Prob. 28PCh. 10 - Prob. 29PCh. 10 - Prob. 30PCh. 10 - Prob. 31PCh. 10 - Prob. 32PCh. 10 - Prob. 33PCh. 10 - Prob. 34PCh. 10 - Prob. 35PCh. 10 - Prob. 36PCh. 10 - Prob. 37PCh. 10 - Prob. 38PCh. 10 - Prob. 39PCh. 10 - Prob. 40PCh. 10 - Prob. 41PCh. 10 - Prob. 42PCh. 10 - Prob. 43PCh. 10 - Prob. 44PCh. 10 - Prob. 45PCh. 10 - Prob. 46PCh. 10 - Prob. 47PCh. 10 - Prob. 48PCh. 10 - Prob. 49PCh. 10 - Prob. 50PCh. 10 - Prob. 51PCh. 10 - Prob. 52PCh. 10 - Prob. 53PCh. 10 - Prob. 54PCh. 10 - Prob. 55PCh. 10 - Prob. 56PCh. 10 - Prob. 57PCh. 10 - Prob. 58PCh. 10 - Prob. 59PCh. 10 - Prob. 60PCh. 10 - Prob. 61PCh. 10 - Prob. 62PCh. 10 - Prob. 63GPCh. 10 - Prob. 64GPCh. 10 - Prob. 65GPCh. 10 - Prob. 66GPCh. 10 - Prob. 67GPCh. 10 - Prob. 68GPCh. 10 - Prob. 69GPCh. 10 - Prob. 70GPCh. 10 - Prob. 71GPCh. 10 - Prob. 72GPCh. 10 - Prob. 73GPCh. 10 - Prob. 74GPCh. 10 - Prob. 75GPCh. 10 - Prob. 76GPCh. 10 - Prob. 77GPCh. 10 - Prob. 78GPCh. 10 - Prob. 79GPCh. 10 - Prob. 80GPCh. 10 - Prob. 81GPCh. 10 - Prob. 82GPCh. 10 - Prob. 83GPCh. 10 - Prob. 84GPCh. 10 - Prob. 85GPCh. 10 - Prob. 86GPCh. 10 - Prob. 87GPCh. 10 - Prob. 88GP
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