Chapter 10, Problem 9P

(a)

To determine

To Find: The total force of atmosphere on the top of a table.

Answer to Problem 9P

The total force of atmosphere acting on the top of a table is $470032\text{ N}$ .

Explanation of Solution

Given info:

Area, $A=1.6\text{ m}\times 2.9\text{ m =}4.64{\text{ m}}^{\text{2}}$

Atmospheric pressure, $P=1\text{atm}=1.013\times {10}^5\text{Pa}$

Formula used:

Write the expression for pressure.

  $P\text{ = }\frac{\text{Force (}F\text{)}}{\text{Area (}A\text{)}}$

Based on the above expression, Force can be written as:

  $F=PA$

Calculation:

Substitute the given values in the above equation,

  $\text{Force (}F)=1.013\times {10}^5\times 4.64=470032\text{ N}$

Conclusion:

Thus, the total force of atmosphere acting on the top of a table is $470032\text{ N}$ .

(b)

To determine

To Find: The total force acting upward on the under the table.

Answer to Problem 9P

The total force acting upward on the underside of the table is same as the force acting on the top of the table.But it is in the opposite direction. So, the total force acting is $\text{470032 N}$ .

Explanation of Solution

Given info:

Area, $A=1.6\text{ m}\times 2.9\text{ m =}4.64{\text{ m}}^{\text{2}}$

Atmospheric pressure, $P=1\text{atm}=1.013\times {10}^5\text{Pa}$

Formula used:

Write the expression for pressure.

  $P\text{ = }\frac{\text{Force (}F\text{)}}{\text{Area (}A\text{)}}$

Based on the above expression, Force can be written as:

  $F=PA$

Calculation:

Substitute the given values in the above equation,

  $\text{Force (}F)=1.013\times {10}^5\times 4.64=470032\text{ N}$

Conclusion:

Thus, the total force acting upward on the underside of the table is same as the force acting on the top of the table but, it is in the opposite direction. So, the total force acting is $470032\text{ N}$ .