Chapter 10, Problem 3P

To determine

To Find: The mass of the gold bricks.

Answer to Problem 3P

The mass of the smuggle gold bricks is $583.63\text{ kg}$ .

Explanation of Solution

Given info:

Volume, $V=60\text{ cm}\times 28\text{ cm}\times 18\text{ cm = }0.6\text{ m}\times 0.28\text{ m}\times 0.18\text{ m = }0.03{\text{ m}}^{\text{3}}$ .

Density of gold bricks, $\rho =19.3\times {10}^3{\text{ kg / m}}^{\text{3}}$ .

Formula used:

Expression of density and mass:

  $\begin{array}{l}\rho \text{ = }\frac{\text{Mass}}{\text{Volume}}\text{ = }\frac{m}{V}\\ m=\rho \times V\end{array}$

Calculation:

Substitute the given values in the above equation:

  $\text{Mass }m=\rho \times V=19.3\times {10}^3\times 0.03=583.63\text{ kg}$

Conclusion:

Thus, the mass of the smuggle gold bricks is $583.63\text{ kg}$ .