Chapter 10, Problem 8Q

To determine

To Explain: Whether an ice cube float in a glass of alcohol or not.

Answer to Problem 8Q

No

Explanation of Solution

Introduction:

Density can be defined as the ration of the mass to the volume.

It is represented as $\rho$

Its SI unit is ${\text{kg/m}}^3$

Mathematically,

  $\text{ρ = }\frac{\text{mass}}{\text{volume}}$

The object having less density in comparison to the liquid will float on the liquid surface while the object having more density in comparison to the liquid will sink in the liquid.

Density of ice ${\rho }_{ice}\text{= 0}\text{.92}{\text{g/cm}}^3$

Density of alcohol, ${\rho }_{alcohol}\text{= 0}\text{.79}{\text{g/cm}}^3$

Since the density of the ice cube is more than that of the alcohol.

Therefore, it will sink in the alcohol

Conclusion:

Ice cube will not float in the glass of the alcohol because of its higher density.