A solution having 75 mEq Na + , 35 mEq K + , 95 mEq Cl − , and 5 mEq NO 3 − is whether possible to prepare has to be determined considering charge-balance. Concept-Introduction: Charge balance takes place when the sum of concentrations of negative ion and the sum of concentrations of positive ion becomes equal in mEq/L or Eq/L concentration units.
A solution having 75 mEq Na + , 35 mEq K + , 95 mEq Cl − , and 5 mEq NO 3 − is whether possible to prepare has to be determined considering charge-balance. Concept-Introduction: Charge balance takes place when the sum of concentrations of negative ion and the sum of concentrations of positive ion becomes equal in mEq/L or Eq/L concentration units.
A solution having 75 mEq Na+, 35 mEq K+, 95 mEq Cl−, and 5 mEq NO3− is whether possible to prepare has to be determined considering charge-balance.
Concept-Introduction:
Charge balance takes place when the sum of concentrations of negative ion and the sum of concentrations of positive ion becomes equal in mEq/L or Eq/L concentration units.
(a)
Expert Solution
Answer to Problem 10.146EP
A solution having 75 mEq Na+, 35 mEq K+, 95 mEq Cl−, and 5 mEq NO3−is not possible to prepare.
Explanation of Solution
Given data is shown below:
Concentration of Na+ = 75 mEqConcentration of K+ = 25 mEqConcentration of NO3− = 5 mEqConcentration of Cl− = 95 mEq
A charge balance exists between the ions in the given electrolyte solution when the sum of Eq/L of positive ions is equal to the sum of Eq/L of negative ions.
Sum of mEq of negative ions is calculated as shown,
Here, the sum of mEq/L of positive ions is not equal to the sum of mEq/L of negative ions
Therefore,
A solution having 75 mEq Na+, 35 mEq K+, 95 mEq Cl−, and 5 mEq NO3−is not possible to prepare.
(b)
Interpretation Introduction
Interpretation:
A solution having 73 Eq K+, 55 Eq Cl−, and 18 Eq C2H3O2− is whether possible to prepare has to be determined considering charge-balance.
Concept-Introduction:
Charge balance takes place when the sum of concentrations of negative ion and the sum of concentrations of positive ion becomes equal in mEq/L or Eq/L concentration units.
(b)
Expert Solution
Answer to Problem 10.146EP
A solution having 73 Eq K+, 55 Eq Cl−, and 18 Eq C2H3O2−is possible to prepare.
Explanation of Solution
Given data is shown below:
Conc of K+= 73 Eq Conc of Cl− = 55 EqConc of C2H3O2− = 18 Eq
A charge balance exists between the ions in the given electrolyte solution when the sum of Eq/L of positive ions is equal to the sum of Eq/L of negative ions.
Sum of Eq of negative ions is calculated as shown,
Hence, the sum of Eq of positive ions is equal to the sum of Eq of negative ions
Therefore,
A solution having 73 Eq K+, 55 Eq Cl−, and 18 Eq C2H3O2−is possible to prepare.
(c)
Interpretation Introduction
Interpretation:
A solution having 750 mEq Na+ and 0.0750 Eq Cl− is whether possible to prepare has to be determined considering charge-balance.
Concept-Introduction:
Charge balance takes place when the sum of concentrations of negative ion and the sum of concentrations of positive ion becomes equal in mEq/L or Eq/L concentration units.
Unit Conversion:
1 Eq = 103 mEq
(c)
Expert Solution
Answer to Problem 10.146EP
A solution having 750 mEq Na+ and 0.0750 Eq Cl−is not possible to prepare.
Explanation of Solution
Given data is shown below:
Concentration of Na+ = 750 mEq Concentration of Cl− = 0.0750 Eq
A charge balance exists between the ions in the given electrolyte solution when the sum of Eq/L of positive ions is equal to the sum of Eq/L of negative ions.
Here, the sum of mEq/L of positive ions is not equal to the sum of mEq/L of negative ions
Therefore,
A solution having 750 mEq Na+ and 0.0750 Eq Cl−is not possible to prepare.
(d)
Interpretation Introduction
Interpretation:
A solution having 0.050 mole Na+, 0.025 mole Ca2+ and 0.075 mole Cl− is whether possible to prepare has to be determined considering charge-balance.
Concept-Introduction:
Charge balance takes place when the sum of concentrations of negative ion and the sum of concentrations of positive ion becomes equal in mEq/L or Eq/L concentration units.
Unit Conversion:
1 Eq = 103 mEq
(d)
Expert Solution
Answer to Problem 10.146EP
A solution having 0.050 mole Na+, 0.025 mole Ca2+ and 0.075 mole Cl−is not possible to prepare.
Explanation of Solution
Given data is shown below:
No. of moles of Na+ = 0.050 moleNo. of moles of Ca2+ = 0.025 moleNo. of moles of Cl− = 0.075 mole
A charge balance exists between the ions in the given electrolyte solution when the sum of Eq/L of positive ions is equal to the sum of Eq/L of negative ions.
(a) The following synthesis of the molecule shown in the circle has a major problem. What is this problem? (2
pts)
1) HBr
(no peroxides)
2) H-
NaNH2
Br
3) NaNH,
4) CH3Br
5) H2, Pd
(b) Starting with the molecule shown below and any other materials with two carbons or less, write out an
alternate synthesis of the circled molecule. More than one step is needed. Indicate the reagent(s) and the major
product in all the steps in your synthesis. (5 pts)
2024 Fall Term (1) Organic Chemistry 1 (Lec)
CHEM 22204 02[6386] (Hunter College)
(c) Using the same starting material as in part (b) and any other materials win two carpons or less, write out
syntheses of the circled molecules shown below. More than one step is needed in each case. Indicate the
reagent(s) and the major product in all the steps in your synthesis. You may use reactions and products from
your synthesis in part (b). (5 pts)
alt
ons for
Free Response Questions
FRQ 1:
0/5
To spectrophotometrically determine the mass percent of cobalt in an ore containing cobalt and
some inert materials, solutions with known [Co?) are prepared and absorbance of each of the
solutions is measured at the wavelength of optimum absorbance. The data are used to create a
calibration plot, shown below.
0.90-
0.80-
0.70
0.60
0.50
0.40-
0.30
0.20-
0.10-
0.00-
0.005
0.010
Concentration (M)
0.015
A 0.630 g sample of the ore is completely dissolved in concentrated HNO3(aq). The mixture is diluted
with water to a final volume of 50.00 ml. Assume that all the cobalt in the ore sample is converted to
Co2+(aq).
a. What is the [Co2] in the solution if the absorbance of a sample of the solution is 0.74?
13
✗
b. Calculate the number of moles of Co2+(aq) in the 50.00 mL solution.
0.008 mols Co
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