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Interpretation: The reason for the ability to solve problems is important in chemistry needs to be explained.
Concept Introduction: All matter is made of chemicals; the importance of chemistry is that it is the study of everything. Chemistry is all about how something interacts to affect the structure, composition, as well as knowing properties of substances.
Answer to Problem 18A
Chemistry is not one of these subjects because it is not something that can simply be memorized. Being able to solve question allows one to get solution to that question. For example, knowing what units’ variables need to be for equations. The methods used to attach a problem are given below:
- Recognizing the question/ problem.
- Propose the possible answer/ solution.
- Decide the suitable answer/ solution.
Explanation of Solution
The meaning of Learning chemistry involves questions- how to be objective, how to reason, and solve problems. In this subject, there are so many variables & consequences. Also, the answer is dependent upon many different concepts, factors, theories, etc.This subject uses both, memory and problem-solving skills.
Problem-solving skills are the standard expression of human thinking. Ability to solve a problem is important in every field of study, not just in chemistry. Problem-solving skills involve analytical, mental, and critical thinking skills to reach to the solutions. Understanding how to set up the problem is just as important as the process. For example: While solving a problem, knowledge of which equation to solve first is extremely important.
The method used to attack a problem is as important as the answer itself. The method should cover the basic steps that are mentioned below:
- Recognizing the question/ problem.
- Propose the possible answer/ solution.
- Decide the suitable answer/ solution.
Chemistry is a fundamental science that investigates and studies molecules.
Chapter 1 Solutions
World of Chemistry, 3rd edition
- Part II. Given two isomers: 2-methylpentane (A) and 2,2-dimethyl butane (B) answer the following: (a) match structures of isomers given their mass spectra below (spectra A and spectra B) (b) Draw the fragments given the following prominent peaks from each spectrum: Spectra A m/2 =43 and 1/2-57 spectra B m/2 = 43 (c) why is 1/2=57 peak in spectrum A more intense compared to the same peak in spectrum B. Relative abundance Relative abundance 100 A 50 29 29 0 10 -0 -0 100 B 50 720 30 41 43 57 71 4-0 40 50 60 70 m/z 43 57 8-0 m/z = 86 M 90 100 71 m/z = 86 M -O 0 10 20 30 40 50 60 70 80 -88 m/z 90 100arrow_forwardPart IV. C6H5 CH2CH2OH is an aromatic compound which was subjected to Electron Ionization - mass spectrometry (El-MS) analysis. Prominent m/2 values: m/2 = 104 and m/2 = 9) was obtained. Draw the structures of these fragments.arrow_forwardFor each reaction shown below follow the curved arrows to complete each equationby showing the structure of the products. Identify the acid, the base, the conjugated acid andconjugated base. Consutl the pKa table and choose the direciton theequilibrium goes. However show the curved arrows. Please explain if possible.arrow_forward
- A molecule shows peaks at 1379, 1327, 1249, 739 cm-1. Draw a diagram of the energy levels for such a molecule. Draw arrows for the possible transitions that could occur for the molecule. In the diagram imagine exciting an electron, what are its various options for getting back to the ground state? What process would promote radiation less decay? What do you expect for the lifetime of an electron in the T1 state? Why is phosphorescence emission weak in most substances? What could you do to a sample to enhance the likelihood that phosphorescence would occur over radiationless decay?arrow_forwardRank the indicated C—C bonds in increasing order of bond length. Explain as why to the difference.arrow_forwardUse IUPAC rules to name the following alkanearrow_forward
- Please correct answer and don't use hand ratingarrow_forwardPlease correct answer and don't use hand ratingarrow_forwardThe SN 1 mechanism starts with the rate-determining step which is the dissociation of the alkyl halide into a carbocation and a halide ion. The next step is the rapid reaction of the carbocation intermediate with the nucleophile; this step completes the nucleophilic substitution stage. The step that follows the nucleophilic substitution is a fast acid-base reaction. The nucleophile now acts as a base to remove the proton from the oxonium ion from the previous step, to give the observed product. Draw a curved arrow mechanism for the reaction, adding steps as necessary. Be sure to include all nonzero formal charges. Cl: Add/Remove step G Click and drag to start drawing a structure.arrow_forward
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