Part IV. C6H5 CH2CH2OH is an aromatic compound which was subjected to Electron Ionization - mass spectrometry (El-MS) analysis. Prominent m/2 values: m/2 = 104 and m/2 = 9) was obtained. Draw the structures of these fragments.
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- Shown below is th carbon NMR spectrum of a compound of the formula C7H14. The compound decolorizes a solution of bromine in dichloromethane. Assign a structure to this hydrocarbon. Correlation of spectrum with number of hydrogen atoms attached to each carbon=A hydrocarbon, compound B, has molecular formula C6H6, and gave an NMR spectrum with two signals: delta 6.55 pm and delta 3.84 pm with peak ratio of 2:1. When warmed in pyridine for three hr, compound B quantitatively converts to benzene. Mild hydrogenation of B yielded another compound C with mass spectrum of m/z 82. Infrared spectrum showed no double bonds; NMR spectrum showed one broad peak at delta 2.34 ppm. With this information, address the following questions. a) How many rings are in compound C? b) How many rings are probably in B? How many double bonds are in B? c) Can you suggest a structure for compounds B and C? d) In the NMR spectrum of B, the up-field signal was a quintet, and the down field signal was a triplet. How must you account for these splitting patterns?The mass spectrum of 1-ethyl-1-methylcyclohexane shows many fragments, with two in very large abundance. One appears at m/z = 111 and the other appears at m/z = 97. Determine the identity and structure of each of these fragments
- A compound of mass 149 has the following elemental analysis : C = 80.48%, H=10.13%, N=9,39%. The IR, 1H and 13C NMR spectra are given below. In the 13C spectrum decoupled from the 1H the nature of the carbon was determined using the 13C DEPT spectra (not shown here). Assign the spectra and identify the compound. You can: 1) Calculate the molecular formula of compound A; 2) Calculate the unsaturation number; 3) Analysethe characteristic bands of the IR spectrum; 4) Assign and interpret all the data from the 1H and 13C NMR spectra). 3500 1800 1600 1400 1200 1000 800 600 cm¹ го протру AU I=3 I=1 I=1 4.0 8.0 I=2 I=2 71 150 3000 с 7.0 CH C 125 2500 6.0 CH 2000 2,8; 40 ppm 5.0 100 Explain why the answer Is this one : 4,5 (6,8; 115) C CH3-NH THÀ ppm ppm 75 3.0 7,2; 128) 132 50 CH₂ 2.0 CH CH₂ 25 CH 3 -CH 3,2; 27 CH3 I=6 1.0 1,2; 22The mass spectrum of 2,3-dimethylpentane [(CH3)2CHCH(CH3)CH2CH3]shows fragments at m/z = 85 and 71. Propose possible structures for theions that give rise to these peaks.Propose a structural formula for the cation at m/z 41 observed in the mass spectrum of methylcyclopentane.
- Treatment of an organic compound with hot, concentrated hydriodic acid(also known as the Zeisel analysis) yields CH3I, indicating the presence of methoxyl group (-OCH3). Unknown organic compound F (one of the opium alkaloids used in antispasmodic medicine whose formula is C19H21NO3) was treated with hot concentrated hydroidic acid to determine the number of methoxyl groups present in the molecule. When 7.12mg of compound F is treated with hydriodic acid and the CH3I thus formed is passed into alcoholic silver nitrate, 10.73mg of silver iodide is obtained. How many methoxyl groups per molecule of compound F would be indicated by the results of this Zeisel analysis?Treatment of compound C (molecular formula C9H12O) with PCC affords D (molecular formula C9H10O). Use the 1H NMR and IR spectra of D to determine the structures of both C and D.Ketones undergo a reduction when treated with sodium borohydride, NaBH4. What is the structure of the compound produced by reaction of 2-butanone with NaBH4 if it has an IR absorption at 3400 cm-1 and M+=74 in the mass spectrum?
- Camphor, a saturated monoketone from the Asian camphor tree, is used among other things as a moth repellent and as a constituent of embalming fluid. If camphor has M+=152.1201 by high-resolution mass spectrometry, what is its molecular formula? How many rings does camphor have?Please find the open chemical structure of the compound. Please indicate your comments on IR, 1H-NMR and Mass Spectrum. Identify IR peaks for the compound’s bonds. Idetify integration values in NMR spectrum for each peak. Show fragmentation in Mass spectrum. Identify molecular ion and base peaks. Explain in details how do you find the open structure of the compound. According to these images;The analysis of the structure of compound X which has the molecular formula C14H10O2 provides spectroscopic data as shown below. By systematic analysis, determine the structure of the compound!