Answered: 5. The existence of compounds of the… | bartleby

Chemistry: Principles and Practice

Chemistry: Principles and Practice

3rd Edition

ISBN:9780534420123

Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer

Chapter10: Molecular Structure And Bonding Theories

Section: Chapter Questions

Problem 10.87QE

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Question

5. The existence of compounds of the noble gases was once a great surprise and stimulated a great
deal of theoretical work. Label the molecular orbital diagram for XeF (include atom chemical symbol,
atomic orbitals, and molecular orbitals) and deduce its ground state electron configuration.
Is XeF likely to have a shorter bond length than XeF+?
XeF
XeF+
Bond Order

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The structure of amphetamine, a stimulant, is shown below. (Replacing one H atom on the NH2, or amino, group with CH3 gives methamphetamine a particularly dangerous drug commonly known as speed.) (a) What are the hybrid orbitals used by the C atoms of the C6 ring. by the C atoms of the side chain, and by the N atom? (b) Give approximate values for the bond angles A, B, and C. (c) How many bonds and bonds are in the molerule? (d) Is the molecule polar or nonpolar? (e) Amphetamine reacts readily with a proton (H+) in aqueous solution. Where does this proton attach to the molecule? Explain how the electrostatic potential map predicts this site of protonation.
The molecular orbital diagram of NO shown in Figure 10.47 also applies to the following species. Write the molecular orbital electron configuration of each, indicating the bond order and the number of unpaired electrons. (a) CN (b) CO (c) BeB (d) BC+ Figure 10.47 Molecular orbital diagram for nitric oxide (NO). The molecular orbital diagram for NO predicts a bond order of 2.5 and predicts that the molecule is paramagnetic with one unpaired electron. These predictions are verified by experimental measurements.
The bond length in C2 is 131 pm. Compare this with the bond lengths in C2H2 (120 pm), C2H4 (134 pm), and C2H6 (153 pm). What bond order would you predict for C2 from its bond length? Does this agree with the molecular orbital configuration you would predict for C2?
Solid sulfur normally consists of crystals of S8 molecules, but when heated strongly, the solid vaporizes to give S2 molecules (among other molecular species). Describe the bonding in S2 in molecular orbital terms, assuming the orbitals are analogous to those of the preceding period. What would you expect to happen to the sulfur sulfur bond length if two electrons were added to give the S22 ion? What would you expect to happen to the bond length if, instead, two electrons were taken away to give S22+?
2. Which of the following species has the largest C—N bond order? CN− OCN− CH3NH2 N(CH3)3
Explain in terms of bonding theory why all four hydrogen atoms of allene, H2CCCH2, cannot lie in the same plane.
What hybrid orbitals would be expected for the central atom in each of the following molecules or ions?
Describe the molecular orbital configurations of C2, C2, and C22. What are the bond orders of these species? Arrange the three species by increasing bond length. Arrange the species by increasing bond enthalpy. Explain these arrangements of bond length and bond enthalpy.
The compound sketched below is acetylsalicylic acid, commonly known as aspirin. (a) What are the approximate values of the angles marked A, B, C, and D? (b) What hybrid orbitals are used by carbon atoms 1, 2, and 3ss?
In each of the following molecules, a central atom is surrounded by a total of three atoms or unshared electron pairs: SnCl2, BCl3, SO2. In which of these molecules would you expect the bond angle to be less than 120? Explain your reasoning.
Do lone pairs about a central atom affect the hybridization of the central atom? If so, how?
Why is the concept of hybridization required in valence bond theory?

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