It is well know that at the same outdoor air temperature a person is cooled at a faster rate under windy conditions that under calm conditions due to the higher convection heat transfer coefficients associated with windy air. The phrase wind-chill is used to relate the rate of heat loss from people under windy conditions to an equivalent air temperature for calm conditions (considered to be a wind or walking speed of 3 mph or 5 km/h). The hypothetical wind-chill temperature (WCT), called the wind-chill temperature index (WCTI), is an air temperature equivalent to the air temperature needed to produce the same temperature (WCT), called the wind-chill temperature index (WCTI), is an air temperature equivalent to the air temperature needed to produce the same cooling effect under calm conditions. A 2003 report on wind-chill temperature by the U.S. National Weather Service gives the WCTI in metric units as WCTI ( ∘ C ) = 13.12 + 0.6215 T − 11.37 V 0.16 + 0.3965 T V 0.16 Where T is the air temperature in ∘ C and V the wind speed in km/h at 10 m elevation. Show that this relations can be expressed in English units as WCTI ( ∘ F ) = 35.74 + 0.6215 T − 35.75 V 0.16 + 0.4275 T V 0.16 Where T is the air temperature in ∘ F and V the wind speed in mph at 33ft elevation. Also, prepare a table for WCTI for air temperatures ranging from 10 to − 60 ∘ C and wind speeds ranging from 10 to 80 km/h. Comment on the magnitude of the cooling effect of the wind and the danger of frostbite.
It is well know that at the same outdoor air temperature a person is cooled at a faster rate under windy conditions that under calm conditions due to the higher convection heat transfer coefficients associated with windy air. The phrase wind-chill is used to relate the rate of heat loss from people under windy conditions to an equivalent air temperature for calm conditions (considered to be a wind or walking speed of 3 mph or 5 km/h). The hypothetical wind-chill temperature (WCT), called the wind-chill temperature index (WCTI), is an air temperature equivalent to the air temperature needed to produce the same temperature (WCT), called the wind-chill temperature index (WCTI), is an air temperature equivalent to the air temperature needed to produce the same cooling effect under calm conditions. A 2003 report on wind-chill temperature by the U.S. National Weather Service gives the WCTI in metric units as WCTI ( ∘ C ) = 13.12 + 0.6215 T − 11.37 V 0.16 + 0.3965 T V 0.16 Where T is the air temperature in ∘ C and V the wind speed in km/h at 10 m elevation. Show that this relations can be expressed in English units as WCTI ( ∘ F ) = 35.74 + 0.6215 T − 35.75 V 0.16 + 0.4275 T V 0.16 Where T is the air temperature in ∘ F and V the wind speed in mph at 33ft elevation. Also, prepare a table for WCTI for air temperatures ranging from 10 to − 60 ∘ C and wind speeds ranging from 10 to 80 km/h. Comment on the magnitude of the cooling effect of the wind and the danger of frostbite.
Solution Summary: The author explains the relation in English unit as WCTI(°F) = 35.74+0.6215T35.75V0.16+0.4275TV0.16, and calculates the change of metric unit to
It is well know that at the same outdoor air temperature a person is cooled at a faster rate under windy conditions that under calm conditions due to the higher convection heat transfer coefficients associated with windy air. The phrase wind-chill is used to relate the rate of heat loss from people under windy conditions to an equivalent air temperature for calm conditions (considered to be a wind or walking speed of 3 mph or 5 km/h). The hypothetical wind-chill temperature (WCT), called the wind-chill temperature index (WCTI), is an air temperature equivalent to the air temperature needed to produce the same temperature (WCT), called the wind-chill temperature index (WCTI), is an air temperature equivalent to the air temperature needed to produce the same cooling effect under calm conditions. A 2003 report on wind-chill temperature by the U.S. National Weather Service gives the WCTI in metric units as
WCTI
(
∘
C
)
=
13.12
+
0.6215
T
−
11.37
V
0.16
+
0.3965
T
V
0.16
Where T is the air temperature in
∘
C
and V the wind speed in km/h at 10 m elevation. Show that this relations can be expressed in English units as
WCTI
(
∘
F
)
=
35.74
+
0.6215
T
−
35.75
V
0.16
+
0.4275
T
V
0.16
Where T is the air temperature in
∘
F
and V the wind speed in mph at 33ft elevation. Also, prepare a table for WCTI for air temperatures ranging from 10 to
−
60
∘
C
and wind speeds ranging from 10 to 80 km/h. Comment on the magnitude of the cooling effect of the wind and the danger of frostbite.
The hydraulic cylinder BC exerts on member AB a force P directed along line BC. The force P must have a 560-N
component perpendicular to member AB.
A
M
45°
30°
C
Determine the force component along line AB.
The force component along line AB is
N.
!
Required information
A telephone cable is clamped at A to the pole AB. The tension in the left-hand portion of the cable is given to be
T₁ = 815 lb.
A
15°
25°
B
T₂
Using trigonometry, determine the required tension T₂ in the right-hand portion if the resultant R of the forces exerted by the cable at
A is to be vertical.
The required tension is
lb.
What are examples of at least three (3) applications of tolerance fitting analysis.
Chapter 1 Solutions
Heat and Mass Transfer: Fundamentals and Applications
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