The molecule shown below is a substrate for trypsin. Draw the reaction products for the lysis of this substrate by trypsin. HN O HN NH -NH₂ NO₂ +H₂N For your answer, follow these guidelines: • Draw all products with the correct ionization at pH 7.0 (for the products of the reaction, assume a pKa of ~3 for any carboxylic acid group and ~ 1 for any amine group that is formed). •. Do not abbreviate any carboxylic acid groups; for example, do not use COOH. • Do not include hydrogens for carbon atoms.

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PLEASE HELP!! The molecule shown below is a substrate for trypsin. Draw the reaction products for the lysis of this substrate by trypsin.

The molecule shown below is a substrate for trypsin. Draw the reaction products for the lysis of this substrate by trypsin.
HN
O
HN
NH
-NH₂
NO₂
+H₂N
For your answer, follow these guidelines:
• Draw all products with the correct ionization at pH 7.0 (for the products of the reaction, assume a pKa of ~3 for any carboxylic acid group and ~ 1 for any amine group
that is formed).
•. Do not abbreviate any carboxylic acid groups; for example, do not use COOH.
• Do not include hydrogens for carbon atoms.
Transcribed Image Text:The molecule shown below is a substrate for trypsin. Draw the reaction products for the lysis of this substrate by trypsin. HN O HN NH -NH₂ NO₂ +H₂N For your answer, follow these guidelines: • Draw all products with the correct ionization at pH 7.0 (for the products of the reaction, assume a pKa of ~3 for any carboxylic acid group and ~ 1 for any amine group that is formed). •. Do not abbreviate any carboxylic acid groups; for example, do not use COOH. • Do not include hydrogens for carbon atoms.
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