This figure represents the ABC operon, which is a negative inducible operon, and itsassociated regulatory gene. The structural genes produced by the operon convertmolecule A into molecule D. When molecule A is present in the environment, it willbind to the regulatory protein, and operon expression will be induced.operatortestRtestRpromoterregulatoryproteintestP testostructural genestest1test1test2test2test3test3structuralproteins The ABC operon has been altered so that some components are mutated. Thegenotype is:testR- testP+ testO+ test1+ test2- test3+In the absence of molecule A, what functional structural proteins are produced fromthe operon?NothingtestRtestPtest1test2test3

Name: This figure represents the ABC operon, which is a negative inducible
Uploaded: 2024-03-20T06:42:41.000Z
Channel: Bartleby
Description: This figure represents the ABC operon, which is a negative inducible operon, and itsassociated regulatory gene. The structural genes produced by the operon convertmolecule A into molecule D. When molecule A is present in the environment, it willbind

Operon is a unit consisting of one or more cistrons systems that function coordinately under the control of an operator gene. In inducible system, the end product inactivates the active repressor and the whole system binds with the operator region of the gene and the transcription stop. In presence of end product the repressor become inactive and the system continues to produce protein. So in this case the end product is known as inducer. Here, testR is a allosteric enzyme or proteins. Allosteric protein have two binding site one (allosteric site) for the binding of inducer molecules and another is for binding to the operator of structural gene. According to the given genotpe (testR - ) is mutated. In this type of mutation active site will changed, so repressor molecules unable to find with operator region. As a result this Opera is always remain active or synthesised structural gene. It doesn't matter weather inducer present or absent. Now, according to given genotypes, test-2-Is mutated and other test-1 and test-3 is normal. So, only test-1 and test-3 functional proteins are produced. Hence, 4th option (test-1) and 6th option (test-3) is correct. Reason for incorrect option: Test-P: promoter not produced any protein. here promoter is normal and serve as binding site for RNA-polymerase. Test-2: it is mutated so it cannot produced any functional protein.