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6) E. coli can use the permease encoded by Lacy to take up the sugar raffinose, however raffinose does not act as an inducer of the lac operon therefore wildtype E. coli cannot grow on raffinose in the absence of lactose because the levels of permease are too low. Genotype I-0+Z+Y•A* I-0+Z*Y*A*/F I+ I-OCZ+Y*A*/F I+ I*0*Z+Y*A*/F 0c ISO*Z*Y*A*/FI+ a) Of the bacterial strains listed in the table (right) which would be able to grow on raffinose in the absence of lactose. Briefly explain/diagram.

6) E. coli can use the permease encoded by Lacy to take up the sugar raffinose, however raffinose does not act as an inducer of the lac operon therefore wildtype E. coli cannot grow on raffinose in the absence of lactose because the levels of permease are too low. Genotype I-0+Z+Y•A* I-0+Z*Y*A*/F I+ I-OCZ+Y*A*/F I+ I*0*Z+Y*A*/F 0c ISO*Z*Y*A*/FI+ a) Of the bacterial strains listed in the table (right) which would be able to grow on raffinose in the absence of lactose. Briefly explain/diagram.

Human Anatomy & Physiology (11th Edition)
Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
Section: Chapter Questions
Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
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6) E. coli can use the permease encoded by LacY to take up the sugar raffinose, however raffinose does not act as an inducer of the lac operon therefore wildtype E. coli cannot grow on raffinose in the absence of lactose because the levels of permease are too low. Genotype I0+Z+Y*A+ I-0+Z*Y*A*/F I+ I-0CZ+Y*A*/F I+ I*0*Z*Y*A*/F 0c ISO*Z+Y*A*/F I+ a) Of the bacterial strains listed in the table (right) which would be able to grow on raffinose in the absence of lactose. Briefly explain/diagram.
Transcribed Image Text:6) E. coli can use the permease encoded by LacY to take up the sugar raffinose, however raffinose does not act as an inducer of the lac operon therefore wildtype E. coli cannot grow on raffinose in the absence of lactose because the levels of permease are too low. Genotype I0+Z+Y*A+ I-0+Z*Y*A*/F I+ I-0CZ+Y*A*/F I+ I*0*Z*Y*A*/F 0c ISO*Z+Y*A*/F I+ a) Of the bacterial strains listed in the table (right) which would be able to grow on raffinose in the absence of lactose. Briefly explain/diagram.
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