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Question 1: The below shows the activities of a small engineering project. Data of the project is given in the below table. The indirect cost is estimated to be SR 140/Day. It required to reduce the project to 17 days. Also draw the contract total cost/time curve and determine the optimum contract duration. Explain your answer. Activity Code A B с D E F G H Activity Code A B C D E F G H Time (day) Normal 4 Duration 8 6 9 4 5 3 7 9 4 5 3 7 Crash 3 6 4 7 1 4 3 6 Depend on A A B,C B,C E D, F Cost (SR) Normal 210 400 500 540 500 150 150 600 Crash 280 560 600 600 1,100 240 150 750

Question 1: The below shows the activities of a small engineering project. Data of the project is given in the below table. The indirect cost is estimated to be SR 140/Day. It required to reduce the project to 17 days. Also draw the contract total cost/time curve and determine the optimum contract duration. Explain your answer. Activity Code A B с D E F G H Activity Code A B C D E F G H Time (day) Normal 4 Duration 8 6 9 4 5 3 7 9 4 5 3 7 Crash 3 6 4 7 1 4 3 6 Depend on A A B,C B,C E D, F Cost (SR) Normal 210 400 500 540 500 150 150 600 Crash 280 560 600 600 1,100 240 150 750

Practical Management Science
Practical Management Science
6th Edition
ISBN:9781337406659
Author:WINSTON, Wayne L.
Publisher:WINSTON, Wayne L.
Chapter2: Introduction To Spreadsheet Modeling
Section: Chapter Questions
Problem 20P: Julie James is opening a lemonade stand. She believes the fixed cost per week of running the stand...
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Question 1: The below shows the activities of a small engineering project. Data of the project is given in the below table. The indirect cost is estimated to be SR 140/Day. It required to reduce the project to 17 days. Also draw the contract total cost/time curve and determine the optimum contract duration. Explain your answer. Activity Code Activity Code A B C D E F G H B C D E F G H Normal 4 8 6 9 4 5 3 7 Duration Time (day) 6 4 5 3 7 Crash 3 6 4 7 1 4 3 6 Depend on Cost (SR) Normal 210 400 500 540 500 150 150 600 A B,C B, C E D, F Crash 280 560 600 600 1,100 240 150 750
Transcribed Image Text:Question 1: The below shows the activities of a small engineering project. Data of the project is given in the below table. The indirect cost is estimated to be SR 140/Day. It required to reduce the project to 17 days. Also draw the contract total cost/time curve and determine the optimum contract duration. Explain your answer. Activity Code Activity Code A B C D E F G H B C D E F G H Normal 4 8 6 9 4 5 3 7 Duration Time (day) 6 4 5 3 7 Crash 3 6 4 7 1 4 3 6 Depend on Cost (SR) Normal 210 400 500 540 500 150 150 600 A B,C B, C E D, F Crash 280 560 600 600 1,100 240 150 750
Initially Activity A B C D E F G H Cost Savings Project cost ND CD CS 4 8 6 9 4 LO 5 3 3 7 6 5250 Project 22 duration 3 70 0 6 80 2 4 50 0 7 30 2 1 200 5 4 90 0 10 TF DS LO Run1 5 150 0 Du TF Indirect cost = 100* 22 = 2200 Direct cost = 3050 Project cost = 2200 + 3050 = SR 5250 Run2 DS Du TF Run 3 Run4 Run5 DS Du TF DS Du TF DS Du TF ND: normal duration; CD: crash duration; CS: cost slope; TF: total float; DS: duration saving; Du: duration
Transcribed Image Text:Initially Activity A B C D E F G H Cost Savings Project cost ND CD CS 4 8 6 9 4 LO 5 3 3 7 6 5250 Project 22 duration 3 70 0 6 80 2 4 50 0 7 30 2 1 200 5 4 90 0 10 TF DS LO Run1 5 150 0 Du TF Indirect cost = 100* 22 = 2200 Direct cost = 3050 Project cost = 2200 + 3050 = SR 5250 Run2 DS Du TF Run 3 Run4 Run5 DS Du TF DS Du TF DS Du TF ND: normal duration; CD: crash duration; CS: cost slope; TF: total float; DS: duration saving; Du: duration
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