Q.1) Solve the rigid plane frame shown in Figure. The frame is fixed at nodes 1 and 3 and subjected to a distributed load of 1000 1 kN/m applied downward over element 2 and a moment of 2 kNm at node 2. The global coordinate axes have been established at node 1. The element lengths are shown in the figure. Let E = 70 GPa, cross section is circular with 50 mm diameter for both elements of the frame. 1 KN/M ༢kln ул 60 -3m- 3. ② -4m→→
Q.1) Solve the rigid plane frame shown in Figure. The frame is fixed at nodes 1 and 3 and subjected to a distributed load of 1000 1 kN/m applied downward over element 2 and a moment of 2 kNm at node 2. The global coordinate axes have been established at node 1. The element lengths are shown in the figure. Let E = 70 GPa, cross section is circular with 50 mm diameter for both elements of the frame. 1 KN/M ༢kln ул 60 -3m- 3. ② -4m→→
Practical Management Science
6th Edition
ISBN:9781337406659
Author:WINSTON, Wayne L.
Publisher:WINSTON, Wayne L.
Chapter5: Network Models
Section: Chapter Questions
Problem 1C
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Transcribed Image Text:Q.1) Solve the rigid plane frame shown in Figure. The frame is fixed at nodes 1 and 3 and subjected
to a distributed load of 1000 1 kN/m applied downward over element 2 and a moment of 2 kNm at
node 2. The global coordinate axes have been established at node 1. The element lengths are shown
in the figure. Let E = 70 GPa, cross section is circular with 50 mm diameter for both elements of
the frame.
1 KN/M
༢kln
ул
60
-3m-
3.
②
-4m→→
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