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Q.1) Solve the rigid plane frame shown in Figure. The frame is fixed at nodes 1 and 3 and subjected to a distributed load of 1000 1 kN/m applied downward over element 2 and a moment of 2 kNm at node 2. The global coordinate axes have been established at node 1. The element lengths are shown in the figure. Let E = 70 GPa, cross section is circular with 50 mm diameter for both elements of the frame. 1 KN/M ༢kln ул 60 -3m- 3. ② -4m→→

Q.1) Solve the rigid plane frame shown in Figure. The frame is fixed at nodes 1 and 3 and subjected to a distributed load of 1000 1 kN/m applied downward over element 2 and a moment of 2 kNm at node 2. The global coordinate axes have been established at node 1. The element lengths are shown in the figure. Let E = 70 GPa, cross section is circular with 50 mm diameter for both elements of the frame. 1 KN/M ༢kln ул 60 -3m- 3. ② -4m→→

Understanding Business
Understanding Business
12th Edition
ISBN:9781259929434
Author:William Nickels
Publisher:William Nickels
Chapter1: Taking Risks And Making Profits Within The Dynamic Business Environment
Section: Chapter Questions
Problem 1CE
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Q.1) Solve the rigid plane frame shown in Figure. The frame is fixed at nodes 1 and 3 and subjected to a distributed load of 1000 1 kN/m applied downward over element 2 and a moment of 2 kNm at node 2. The global coordinate axes have been established at node 1. The element lengths are shown in the figure. Let E = 70 GPa, cross section is circular with 50 mm diameter for both elements of the frame. 1 KN/M ༢kln ул 60 -3m- 3. ② -4m→→
Transcribed Image Text:Q.1) Solve the rigid plane frame shown in Figure. The frame is fixed at nodes 1 and 3 and subjected to a distributed load of 1000 1 kN/m applied downward over element 2 and a moment of 2 kNm at node 2. The global coordinate axes have been established at node 1. The element lengths are shown in the figure. Let E = 70 GPa, cross section is circular with 50 mm diameter for both elements of the frame. 1 KN/M ༢kln ул 60 -3m- 3. ② -4m→→
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