40001008060IR Spectrum(liquid film)4020$2296030004177794013C NMR Spectrum(50.0 MHz. CDCI, solution)proton decoupled200¹H NMR Spectrum(200 MHz, CDCI, solution)T4010 9802000107/10918120v (cm¹)m/e1600M**156/158/1601601603.51200120200 240766800Mass Spectrumexpansionsppm2.517 6 5650C3H6Br Cl280T2.0 ppmsolvent804H-C-HProblem 18No significant UVabsorption above 220 nmH-C-H1340H-C-H012 11248 (ppm)TMS08 (ppm)107

Answered: Image /qna-images/answer/a570b991-2b03-46eb-abc3-6f75f7535229.jpg

IR Spectrum (quid film) 4000 100 80 Få 60 s ta 408 20 TTT 2960 3000 41 77 40 80 13C NMR Spectrum (50.0 MHz. CDCI, solution) proton decoupled 200 2000 107/109 120 V (cm¹) 1600 M** 156/158/160 160 m/e 160 200 120 1200 766 240 650 800 Mass Spectrum C3HgBrCl 280 solvent 80 H-C-H Problem 18 No significant UV absorption above 220 nm H-C-H 40 H-C-H 0 124 8 (ppm)

IR Spectrum (quid film) 4000 100 80 Få 60 s ta 408 20 TTT 2960 3000 41 77 40 80 13C NMR Spectrum (50.0 MHz. CDCI, solution) proton decoupled 200 2000 107/109 120 V (cm¹) 1600 M** 156/158/160 160 m/e 160 200 120 1200 766 240 650 800 Mass Spectrum C3HgBrCl 280 solvent 80 H-C-H Problem 18 No significant UV absorption above 220 nm H-C-H 40 H-C-H 0 124 8 (ppm)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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IR Spectrum (liquid film) 184 4000 100 80 60 40 20 40 13C NMR Spectrum (50.0 MHz, CDCI, solution) proton decoupled 200 ¹H NMR Spectrum (600 MHz, CDCI, solution) 1 10 9 8 3000 % of base peak 80 128 my 2000 V (cm¹) 119 M+* 134 120 160 m/e expansion 124 ppm 160 1600 I 7 200 I 6 120 ppm 1200 800 Mass Spectrum C10 H14 280 solvent 80 240 I 5 7.4 1 4 expansion 3 Problem 95 UV Spectrum max 262 nm (log10 € 2.5) solvent: ethanol -CH3 C 40 7.2 2 1 0 8 (ppm) TMS 1 I 1 0 8 (ppm) 201
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