00 trum IR Spectrum (liquid fem) 4000 100 80 60 % of base peak 3000 54 68 40 13C NMR Spectrum (100 MHz, CDC, solution) 80 DEPT CHI CHI CHA proton decoupled 200 ¹H NMR Spectrum (200 MHz. CDCI, solution) 2249 2000 v (cm¹) 1600 M 147/149 120 160 m/e 160 expansion 1200 800 Mass Spectrum CHENBr 280 200 240 120 solvent 1 80 Problem 19 No significant UV absorption above 220 nm 40 0 125 8 (ppm)

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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m
00
trum
solutic
4000
88892
IR Spectrum
(liquid fem)
100
80
60
40
20
% of base peak
m
1600
v (cm¹)
68
M 147/149
40 80 120 160
m/e
13C NMR Spectrum
(100 MHz. CDC, solution)
10
3000
54
DEPT CHY CH1 CHA
proton decoupled
200
¹H NMR Spectrum
(200 MHz. CDCI, solution)
108
2249
2000
160
expansion
34
30
26
9 8 7
1200
800
Mass Spectrum
C₂H6NBr
200 240 280
120
22 ppm
6 5
solvent
1
80
4
Problem 19
No significant UV
absorption above 220 nm
40
3
0
125
8 (ppm)
TMS
1
0
8 (ppm)
2 1
Transcribed Image Text:m 00 trum solutic 4000 88892 IR Spectrum (liquid fem) 100 80 60 40 20 % of base peak m 1600 v (cm¹) 68 M 147/149 40 80 120 160 m/e 13C NMR Spectrum (100 MHz. CDC, solution) 10 3000 54 DEPT CHY CH1 CHA proton decoupled 200 ¹H NMR Spectrum (200 MHz. CDCI, solution) 108 2249 2000 160 expansion 34 30 26 9 8 7 1200 800 Mass Spectrum C₂H6NBr 200 240 280 120 22 ppm 6 5 solvent 1 80 4 Problem 19 No significant UV absorption above 220 nm 40 3 0 125 8 (ppm) TMS 1 0 8 (ppm) 2 1
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