4000 100 2892 80 adadadadad IR Spectrum (quid fim 60 % of base peak 3000 57 12. 99 40 80 13C NMR Spectrum (50.0 MHz. CDCI, solution) DEPT CH CH, CH proton decoupled 200 1H NMR Spectrum (200 MHz, CDCl3 solution) 10 9 8 2000 v (cm'¹) More branch Ciao M-114 (<1%) 160 دفع 120 m/e 160 1600 7 200 120 6 1200 800 Mass Spectrum C8H18 280 240 5 solvent 80 1 4 I Problem 8 No significant UV absorption above 220 nm 2 x 8 + 18 28 16+ 18-(6) 1²6 x ¹2² = 1878- = 20/0 CASA 15-0 CH3 8(ppm) 3 40 وادر 2 0 1 114 TMS L 0 & (pn

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
What is the IR and HNMRAndCNMR and mass
4000
100
IR Spectrum
(quid im
80
8888
% of base peak
3000
57
40
13C NMR Spectrum
(50.0 MHz. CDCI, solution)
10 9
I'
99
80
DEPT CH₂ CH₂ CH
proton decoupled
200
¹H NMR Spectrum
(200 MHz, CDC3 solution)
8
2000
v (cm')
More branch
مها مفرح
120
M-114 (<1%)
160
m/e
1600
160
1
7
#
240
200
120
1200
6
800
Mass Spectrum
C8H18
280
5
solvent
1
80
4
Problem 8
No significant UV
absorption above 220 nm
2 x 8 + 18 (28)
16+ 18-(6)
16 x ¹2²=1878 = (=
=2010
فتظم
3
40
واحد ص
2
0
1
114
CAs Asym
1500
CH3 Sy
8 (ppm) 340
TMS
L 1
0
8 (ppm)
Transcribed Image Text:4000 100 IR Spectrum (quid im 80 8888 % of base peak 3000 57 40 13C NMR Spectrum (50.0 MHz. CDCI, solution) 10 9 I' 99 80 DEPT CH₂ CH₂ CH proton decoupled 200 ¹H NMR Spectrum (200 MHz, CDC3 solution) 8 2000 v (cm') More branch مها مفرح 120 M-114 (<1%) 160 m/e 1600 160 1 7 # 240 200 120 1200 6 800 Mass Spectrum C8H18 280 5 solvent 1 80 4 Problem 8 No significant UV absorption above 220 nm 2 x 8 + 18 (28) 16+ 18-(6) 16 x ¹2²=1878 = (= =2010 فتظم 3 40 واحد ص 2 0 1 114 CAs Asym 1500 CH3 Sy 8 (ppm) 340 TMS L 1 0 8 (ppm)
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