IR Spectrum (KB/ disc) 4000 ent % of base peak 3000 44 100 80 60 40 20 40 13C NMR Spectrum (100.0 MHz. D₂0 solution) 74 M+¹-89 80 120 DEPT CH₂ CH, CH4 proton decoupled 200 1620 V (cm'¹) 2000 160 m/e 160 1600 200 120 mm 1200 800 Mass Spectrum C3H7NO₂ 240 280 80 Problem 20 No significant UV absorption above 220 nm 0 40 126 8 (ppm)

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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What is the IR and HNMRAndCNMR and mass in this example explain and chemical shift
100
80
g
ململململململه
4000
60
IR Spectrum
(KBr disc)
10
% of base peak
40
20
40
13C NMR Spectrum
(100.0 MHz. D₂0 solution)
3000
44
DEPT CH₂ CH, CH
proton decoupled
200
¹H NMR Spectrum
(400 MHz. D₂0 solution)
Note: there are 3 protons
which exchange with
the D₂0 solvent
3.9
1
9
74 M 89
80
expansions
3.7 ppm
1
8
16
1620
V (cm¹)
2000
L
120 160
m/e
160
1600
1.4 ppm
200
120
1200
800
Mass Spectrum
C3H7NO₂
240 280
80
H₂O and HOD
in solvent
L J
7 6 5
4 3
Problem 20
No significant UV
absorption above 220 nm
0
2 1
40
126
8 (ppm)
0
8 (ppm)
109
Transcribed Image Text:100 80 g ململململململه 4000 60 IR Spectrum (KBr disc) 10 % of base peak 40 20 40 13C NMR Spectrum (100.0 MHz. D₂0 solution) 3000 44 DEPT CH₂ CH, CH proton decoupled 200 ¹H NMR Spectrum (400 MHz. D₂0 solution) Note: there are 3 protons which exchange with the D₂0 solvent 3.9 1 9 74 M 89 80 expansions 3.7 ppm 1 8 16 1620 V (cm¹) 2000 L 120 160 m/e 160 1600 1.4 ppm 200 120 1200 800 Mass Spectrum C3H7NO₂ 240 280 80 H₂O and HOD in solvent L J 7 6 5 4 3 Problem 20 No significant UV absorption above 220 nm 0 2 1 40 126 8 (ppm) 0 8 (ppm) 109
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