2IR Spectrum(liquid film)40001008020my2251% of base peak300040 8013C NMR Spectrum(100.0 MHz, CDCI, solution)10DEPT CH₂ CH₂ CHproton decoupled200¹H NMR Spectrum(400 MHz. CDCI, solution)20009 8v (cm¹)M 117120 160 200m/eexpansion130 129130 1291600expansion160ppmppm1201200800Mass SpectrumC8H7N240280solvent180407 6 5 4 3 20 8 (ppm)1TMSL08 (ppm)

IR spectra are used to identify the functional groups of unknown compounds.Mass spectra are used to…

myw 2251 IR Spectrum (liquid film) 4000 100 80 % of base peak 3000 J 40 13C NMR Spectrum (100.0 MHz, CDCI, solution) 10 DEPT CH₂ CH₂ CH proton decoupled 200 ¹H NMR Spectrum (400 MHz. CDC, solution) 9 2000 8 91 80 120 160 m/e v (cm'¹) M 117 expansion 1600 130 129 ppm expansion 130 129 ppm 160 7 6 1200 120 800 Mass Spectrum 200 240 280 5 CgH7N solvent 80 4 3 40 2 0 1 8 (ppm) TMS L 0 8 (ppm)

myw 2251 IR Spectrum (liquid film) 4000 100 80 % of base peak 3000 J 40 13C NMR Spectrum (100.0 MHz, CDCI, solution) 10 DEPT CH₂ CH₂ CH proton decoupled 200 ¹H NMR Spectrum (400 MHz. CDC, solution) 9 2000 8 91 80 120 160 m/e v (cm'¹) M 117 expansion 1600 130 129 ppm expansion 130 129 ppm 160 7 6 1200 120 800 Mass Spectrum 200 240 280 5 CgH7N solvent 80 4 3 40 2 0 1 8 (ppm) TMS L 0 8 (ppm)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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m 00 trum solutic 4000 88892 IR Spectrum (liquid fem) 100 80 60 40 20 % of base peak m 1600 v (cm¹) 68 M 147/149 40 80 120 160 m/e 13C NMR Spectrum (100 MHz. CDC, solution) 10 3000 54 DEPT CHY CH1 CHA proton decoupled 200 ¹H NMR Spectrum (200 MHz. CDCI, solution) 108 2249 2000 160 expansion 34 30 26 9 8 7 1200 800 Mass Spectrum C₂H6NBr 200 240 280 120 22 ppm 6 5 solvent 1 80 4 Problem 19 No significant UV absorption above 220 nm 40 3 0 125 8 (ppm) TMS 1 0 8 (ppm) 2 1
IR Spectrum (liquid film) 184 4000 100 80 60 40 20 40 13C NMR Spectrum (50.0 MHz, CDCI, solution) proton decoupled 200 ¹H NMR Spectrum (600 MHz, CDCI, solution) 1 10 9 8 3000 % of base peak 80 128 my 2000 V (cm¹) 119 M+* 134 120 160 m/e expansion 124 ppm 160 1600 I 7 200 I 6 120 ppm 1200 800 Mass Spectrum C10 H14 280 solvent 80 240 I 5 7.4 1 4 expansion 3 Problem 95 UV Spectrum max 262 nm (log10 € 2.5) solvent: ethanol -CH3 C 40 7.2 2 1 0 8 (ppm) TMS 1 I 1 0 8 (ppm) 201
What is the IR and HNMRAndCNMR and mass
MASS % of Base Peak IR 100 5045 % Transmittance 100 T 50 4000 1540 ¹H NMR 300 MHz t 557 5.0 Hz 60 alla illle 677 69 1140 4.5 70 4.0 13C/DEPT NMR 75.5 MHz 3000 130 120 110 100 الد الله da 110 113 100 110 mm 817 Hz 500 90 80 m/z Wavenumber (cm-¹) 3.5 ми линия 80 90 480 Hz 957 3.0 70 2000 440 2.5 Hz 1450 2.0 -1126 120 1000 60 50 40 30 1287 130 1.5 ppm 20 ppm
Assign each 13C of the molecule below to a peak in the following 13C NMR spectrum. Ideally, you will label the peaks on the spectrum from left to right as C1 through C8. حمد
What is the IR and HNMRAndCNMR and mass
What is the IR and HNMRAndCNMR and mass
I got this question wrong on my exam and don't know why. Could you please explain?
What is the IR and HNMRAndCNMR and mass
What is the IR and HNMRAndCNMR and mass in this example
What is the IR and HNMRAndCNMR and mass in this example
What is the IR and HNMRAndCNMR and mass in this example explain