4000 88898 IR Spectrum 100 of base peak 3000 40 80 13C NMR Spectrum (500 MHz. CDC, solution) 100 DEPT CHT CH, CHI proton decoupled 200 ¹H NMR Spectrum (200 MHz, CDCI, solution) 10 9 8 2000 1743 1600 v (cm¹) 800 Mass Spectrum M-174 (<1%) C8H₁404 120 160 200 240 280 m/e solvent 80 160 7 6 120 1200 5 3 Problem 49 No significant UV absorption above 220 nm 0 40 1 2 1 8 (ppm) TMS L 0 8 (ppm)

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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What is the IR and HNMRAndCNMR and mass in this example explain
L
4000
100
IR Spectrum
8898
% of base peak
3000
57
40
13C NMR Spectrum
(50.0 MHz. CDC), solution)
80
100
DEPT CH₂ CH₂ CH
proton decoupled
200
¹H NMR Spectrum
(200 MHz, CDCI, solution)
10
9
8
138
2000
120
160
p
1600
1743
v (cm¹)
7
m/e
M-174 (<1%)
160
6
1200
120
200 240
800
Mass Spectrum
m
5
C8H₁404
280
solvent
80
4
3
Problem 49
No significant UV
absorption above 220 nm
40
H
2
0
1
8 (ppm)
TMS
0
8 (ppm)
Transcribed Image Text:L 4000 100 IR Spectrum 8898 % of base peak 3000 57 40 13C NMR Spectrum (50.0 MHz. CDC), solution) 80 100 DEPT CH₂ CH₂ CH proton decoupled 200 ¹H NMR Spectrum (200 MHz, CDCI, solution) 10 9 8 138 2000 120 160 p 1600 1743 v (cm¹) 7 m/e M-174 (<1%) 160 6 1200 120 200 240 800 Mass Spectrum m 5 C8H₁404 280 solvent 80 4 3 Problem 49 No significant UV absorption above 220 nm 40 H 2 0 1 8 (ppm) TMS 0 8 (ppm)
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