4000 100 38898 IR Spectrum (liquid film) 80 MMMMM % of base peak 10 3000 43 40 13C NMR Spectrum (50 0 MHz. CDCI, solution) 5.5 59 9 87 DEPT CH₂ CH₂ CH proton decoupled 200 ¹H NMR Spectrum (200 MHz, CDCI, solution) expansions 80 2.5 45 ppm 8 nm homm 1747 1200 800 1600 v (cm'¹) Mass Spectrum M 146 C6H1004 120 160 m/e 2000 160 7 200 240 280 solvent 120 15 ppm 6 5 80 4 3 40 Problem 47 No significant UV absorption above 220 nm 2 0 8 (ppm) 1 0 8 (ppm)

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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What is the IR and HNMRAndCNMR and mass in this example
4000
100
80
8898
wwwwww
60
IR Spectrum
(liquid film)
40
20
% of base peak
10
40
13C NMR Spectrum
(50 0 MHz. CDCI, solution)
136
3000
43
55
59
DEPT CH₂ CH₁ CH
proton decoupled
200
¹H NMR Spectrum
(200 MHz, CDCI, solution)
expansions
9
87
80
2000
120
V (cm¹)
M+
146
160
m/e
ypa
1747
1600
1200
160
120
44
T
25
1.5
ppm
45 ppm
6
7
8
200 240
800
Mass Spectrum
C6H1004
280
5
solvent
80
4
3
40
Problem 47
No significant UV
absorption above 220 nm
08 (ppm)
0
8 (ppm)
1
2
1
Transcribed Image Text:4000 100 80 8898 wwwwww 60 IR Spectrum (liquid film) 40 20 % of base peak 10 40 13C NMR Spectrum (50 0 MHz. CDCI, solution) 136 3000 43 55 59 DEPT CH₂ CH₁ CH proton decoupled 200 ¹H NMR Spectrum (200 MHz, CDCI, solution) expansions 9 87 80 2000 120 V (cm¹) M+ 146 160 m/e ypa 1747 1600 1200 160 120 44 T 25 1.5 ppm 45 ppm 6 7 8 200 240 800 Mass Spectrum C6H1004 280 5 solvent 80 4 3 40 Problem 47 No significant UV absorption above 220 nm 08 (ppm) 0 8 (ppm) 1 2 1
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