3310 IR Spectrum (quid m 4000 100 BO % of base peak 3000 40 13C NMR Spectrum (100 0 MHz, CDC, solution) 80 DEPT CH₂ CH CH proton decoupled 200 ¹H NMR Spectrum (200 MHz. CDCI, solution) 10 9 8 mp 2000 1600 1200 106 120 v (cm¹) m/e 160 160 7 M 197 200 6 expansion 128 ppm expansion 129 128 ppm 129 120 800 Mass Spectrum CH5N 240 280 5 solvent 80 st 4 Problem 37 3 40 0 exchanges with D₂0 £ 2 1 8 (ppm) TMS L 0 8 (ppm)

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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What is the IR and HNMRAndCNMR and mass in this example explain
4000
100
80
3310
IR Spectrum
(quid film)
badadadadadad
% of base peak
3000
91
80
40
13C NMR Spectrum
(100 0 MHz, CDC, solution)
DEPT CH₂ CH CH
proton decoupled
200
¹H NMR Spectrum
(200 MHz. CDCI, solution)
10
9
8
www.m
1600
1200
800
2000
v (cm)
Mass Spectrum
CHEN
280
106
120 160
m/e
160
7
M
197
200
129
6
129
120
240
expansion
128 ppm
expansion
128 ppm
5
solvent
80
4
Problem 37
3
40
0
exchanges
with D₂O
£
2
1
8 (ppm)
TMS
L
0
8 (ppm)
Transcribed Image Text:4000 100 80 3310 IR Spectrum (quid film) badadadadadad % of base peak 3000 91 80 40 13C NMR Spectrum (100 0 MHz, CDC, solution) DEPT CH₂ CH CH proton decoupled 200 ¹H NMR Spectrum (200 MHz. CDCI, solution) 10 9 8 www.m 1600 1200 800 2000 v (cm) Mass Spectrum CHEN 280 106 120 160 m/e 160 7 M 197 200 129 6 129 120 240 expansion 128 ppm expansion 128 ppm 5 solvent 80 4 Problem 37 3 40 0 exchanges with D₂O £ 2 1 8 (ppm) TMS L 0 8 (ppm)
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