110Problem 4IR Spectrum(CCI solution)menhsl propionate17444000300020001600V (cm')1200800100578029Mass Spectrum6040No significant UVabsorption above 220 nmM*- 8820CAHBO24080120160m/e20024028013C NMR Spectrum(100.0 MHz. CDCI, solution)DEPT CH CH, CHtsolventproton decoupled0.8 (ppm)1208040200160H NMR Spectrum(200 MHz, CDCI, solution)expansionTMSppm1.02.048 (ppm76.10% of base peak

Molecular formula = C4H8O * Double bond equivalence = 4+1-(8÷2) = 1 Only one double bond is…

110 Problem 4 IR Spectrum (CCl solution) menhsl propionate 1744 4000 3000 2000 1600 V (cm') 1200 800 100 57 80 29 Mass Spectrum 60 40 No significant UV M*- 88 absorption above 220 nm 20 CAH&O2 40 80 120 160 m/e 200 240 280 13C NMR Spectrum (100.0 MHz. CDCI, solution) DEPT CH, CH, сн solvent proton decoupled 0. 8 (ppm) 80 40 160 120 200 H NMR Spectrum (200 MHz. CDCI, solution) expansion TMS 1.0 ppm 2.0

110 Problem 4 IR Spectrum (CCl solution) menhsl propionate 1744 4000 3000 2000 1600 V (cm') 1200 800 100 57 80 29 Mass Spectrum 60 40 No significant UV M*- 88 absorption above 220 nm 20 CAH&O2 40 80 120 160 m/e 200 240 280 13C NMR Spectrum (100.0 MHz. CDCI, solution) DEPT CH, CH, сн solvent proton decoupled 0. 8 (ppm) 80 40 160 120 200 H NMR Spectrum (200 MHz. CDCI, solution) expansion TMS 1.0 ppm 2.0

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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