116Problem 10IR Spectrum(KBr disc)14=12+216934000(02F14-8 2CH23000200016001200B00V (cm')100C=0256Mass Spectrum80M* 11260No significant UVabsorption above 220 nm4020CeHgO212+2-06/4440120m/e8016020024028013C NMR Spectrum(100 O MHz. CDCI, solution)DEPT CH, CH,t CHtproton decoupledsolvent20016012080408 (ppm)H NMR Spectrum(400 MHz, CDCI, solution)TMS18 (ppm76.432109.

First, we have to calculate the double bond equivalence (DBE) of the molecular formula C6H8O2 by…

Answered: IR Spectrum (KBr disc) 1693 4000 3000…

IR Spectrum (KBr disc) 1693 4000 3000 800 2000 1600 V (cm') 1200 10아 Mass Spectrum 56 80 M*112 60 40 20 CeH8O2 40 80 120 160 200 240 280 % of base peak

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Q: MS: m/z=148 (M,100%),149 (11%) IR (liquid film): 3077‐2835 (multitude of weak peaks)…

A: The IR peaks observed are as shown below:IR (liquid film): 3077‐2835 (multitude of weak peaks),…

Q: 2.5 100- 80 60 40 20 0 4000 STRANSMITTANCE O=C-H saturated C-H 3500 3.5 3000 N-H alcohol O-H 4 4.5…

A: 3300 cm-1 is N-H stretch, 3050 cm-1 is sp2 C-H stretch, 2900 cm-1 sp3 C-H stretch, 1620 cm-1 C=C…

Q: 透过率/% 100 20 D 12.1 Which compound is consistent with the spectrum shown below? 薄膜法 4000 1982 8B 26…

A: Infrared (IR) spectroscopy is an analytical technique which is aimed at structural elucidation. Most…

Q: 1054.00 38 1581.98 1032.45 1015.76 100 92 2971.78 2964.30 2842.98 3679 07 1592.72 1574.49 1426.29…

Q: 4000 100 во % of base peak 3376 3000 59 60 40 20 40 13C NMR Spectrum (50.0 MHz, CDC, solution) 80 IR…

A: The Proton NMR shows us the no of different types of hydrogens present in the given organic…

Q: Sample ID:ethyl alcohol_BSCOS3A Sample Scans:32 Agilent Technologies Background Scans:32…

A: The question is based on the concept of IR spectroscopy. we need to analyse the spectra and identify…

Q: IR Spectrum d) Wat 4000 100 80 60 41 43 40 10 3000 "C NMR Spectrum (150 MHz, CDC, skon) proton…

A: Given that, the molecular formula of a compound is C5H9N. Also, it's IR, mass, and 1H NMR spectra…

Q: Match the following compounds to the given IR spectra. On each IR spectrum, label the absorptions…

A: To match the given IR spectra to one of the compounds.

Q: Transmitance 0.8 0.6 0.4 0.2 4000 3000 INFRARED SPECTRUM 2000 1000

A: The question is based on the concept of organic spectroscopy. We need to analyse the spectral data…

Q: Using the given spectra, determine the Identity of the compound the spectra describes and explain…

A: Step 1: Step 2: Step 3: Step 4:

Q: 1) Formula: C4H10O2 PPM Broad singlet (2H) Multiplet (2H) Integration 1.114 6H 3.764 2H 3.998 2H ma…

A: I'll guide you through solving this NMR spectroscopy problem step by step. Step 1: Analyze the given…

Q: Identify the parent and propose a structure for the base peak in the mass spectrum of butan-1-amine.

A: Parent peak: In the mass spectrum M+ peak is known as parent peak and it is occurs in most left in…

Q: 5. An unknown compound, has the formula C7H₁4O. Explain and elucidate the structure by scrutinizing…

A: DBE is Double Bond Equivalent. This DBE value gives idea about number of doublr bond, triple bond…

Q: 3500 3000 2500 Wavenumber (cm-1) 2000 1500 1000 Identify an unknown alcohol (1-butanol, isoamyl…

A: Infrared spectroscopy is the study of interaction of infrared light with matter, which can be used…

Q: The mass spectrum below is for which Relative Intensity 0000 120 100 80 40 20 0 10 O Propane…

A: Mass spectrometry is one of the best techniques for analyzing the structure of a molecule and…

Q: Is the product pure? how do you know? here is the results: Starting mass of benzyl 1.0883g…

A: If experimental melting point of the concerned molecule is different compare to actual melting…

Q: 1657.91cm-1, 96.43%T 1408.47cm-1, 93.44%T 555.79cm-1. 94.98%T 1338.31cm-1, 94.20%T 671.77cm-1,…

A: The question is based on the concept of IR Spectroscopy. we have to analyse the spectra provided…

Q: 6 IR: strong peak at 1750cm-1 1H 3+2= 3 PPM 3H 6H

Q: Interpret the IR spectrum.

A: In the IR spectrum, a sharp peak at 1600 cm-1 indicates the presence of aromatic C=C bond. The peak…

Q: None

A: Answer image:Step 1:b.The given spectra have the following peaks broad peak : 3200 -2500 cm-1 : due…

Q: 3295 IR Spectrum (liquid film) 4000 3000 2114 2000 m nnt 1600 (cm¹) 1200 800

A: The objective of the question is to interpret the given Infrared (IR) spectrum values and determine…

Q: IR Spectrum (quid fem 4000 100 80 60 40 20 40 13C NMR Spectrum (500 MHz, CDC), solution) of base…

Q: 100 80 60 40 20 % of base peak 40 45 59 V (cm¹) M+ = 60 (<1%) 120 80 160 m/e 800 Mass Spectrum 1200…

Q: (1) H、 CH3CH2OC O 3, 39D C=C || COCH 2CH 3 H

Q: The infrared spectrum, shown below, is that of a carboxylic acid after the oxidation of a tertiary…

A: The infrared (IR) spectrum provided in the image is to be analyzed to determine whether it…

Q: IR Spectrum (quid film) 4000 100 80 60 40 20 % of base peak 3000 41 80 200 ¹H NMR Spectrum (400 MHz,…

Q: MASS SPECTRUM 100 - Relative Intensities: 80 m/z 121- 100% m/z 194- 21% 60 m/z 195- 3% 40 20 0.0 0.0…

A: Please find the below attachment. If you do not want to rate please let it be. It will effect my…

Q: % transmittance 4000 3.0 OH (broad) carboxylic acid 3500 2.6 broad 1 H singlet at 10.7 ppm 2 CH…

A: The question is based on the concept of organic spectroscopy. We need to analyse the spectral data…

Q: Part 5: Putting It All Together We don't quite have all the parts of an NMR analysis yet, but we can…

A: The explanation is given below-

Q: what molecules is this

Q: 4958 METHYL-M-NITROBENZOATE-CARBON 200 180 160 140 120 100 80 60 40 20 ppm 86 9T 8- - 52.7

A: Given compound,

Q: The intensities of peaks at 69 m/z, 70 m/z, and 71 m/z are 1.2, 31.2, and 1.7, respectively. How…

A: A question based on Mass spectrum, which is to be accomplished.

Q: 11. The mass spectral data of an unknown liquid is given below. What is the molecular formula of…

A: M+ peak indicates the molecular mass of the compound.

Q: The intensity of M+, M+1, and M+2 peak are 100.0, 6.8, 31.9. How many carbons are in the compound?…

A: A mass spectrum is an important tool for the determination of the mass of a compound. A mass…

Q: IR Spectrum (quid film) 4000 100 80 Få 60 s ta 408 20 TTT 2960 3000 41 77 40 80 13C NMR Spectrum…

Q: 19. For Ha, how many non-equivalent protons are on the adjacent carbon atoms (that is, how many…

A: 19. For Ha, the number of non-equivalent protons on adjacent carbon is two(Hb ). 20 . n is the…

Q: Match a structure with the correct IR spectrum. You will, of course, notice that there are more…

A: here we are required to find the IR spectra which matches correctly with the given compound

Q: MS Relative Intensity 100 80 60 40 20 0 10 20 30 40 50 60 70 m/z 80 90 100 M+ 110 120 m.w. 106 2-p…

A: The question is based on the concept of mass spectroscopy . we need to analyse the spectra &…

Q: In the above spectrum, why are there two signals?

A: Since, since you have posted multiple questions, we will solve only the first 3 questions related to…

Q: C2H5ClO2 elucidate thefollowing spectrum and identify the unknown compound

Q: Spectrum A 2H ΤΗ 2Η 8 7 3 H 8 7 6. 2 4 PPM 3 1

Q: In a GCMS experiment, a compound shows a 1:1 height ratio of its M peak at 122 mass units and its…

Q: Identify the name of the compound and draw the structure that conforms the mass spectrum below.…

A: A question based on mass spectrum, which is to be accomplished.

Q: Page > of 3 2 ZOOM 6. IR Spectra: 100 3000 2008 1000 S00 波数/cm 3476 62 3461 14 2828 66 2679 57 1604…

A: In the IR spectrum of p-aminobenzoic acid, we will observe peaks for the vibrations of the primary…

Q: A compound Y is to be determined by UV-visible spectrophotometry. A calibration curve is constructed…

A: The data given is, Concentration (ppm) Absorbance 0.20 0.870 0.40 0.840 0.60 0.800 0.80…

Q: Mass Spectrum 100- 1H NMR Spectrum 6H M (74) = 100% M+1 (75) = 4.52 M+2 (76) = 0.28 doublet 80- 2H…

Concept explainers

Mass Spectrometry

This process is an instrumental method in which a sample is changed to fast moving positive ions by electron bombardment. The charged particles vary due to their different mass to charge ratio and are estimated with the help of this difference. It is also called mass spectroscopy.

Question

116
Problem 10
IR Spectrum
(KBr disc)
14=12+2
1693
4000
(02F14-8 2
CH2
3000
2000
1600
1200
B00
V (cm')
100
C=02
56
Mass Spectrum
80
M* 112
60
No significant UV
absorption above 220 nm
40
20
CeHgO2
12+2-06/44
40
120
m/e
80
160
200
240
280
13C NMR Spectrum
(100 O MHz. CDCI, solution)
DEPT CH, CH,t CHt
proton decoupled
solvent
200
160
120
80
40
8 (ppm)
H NMR Spectrum
(400 MHz, CDCI, solution)
TMS
1
8 (ppm
7
6.
4
3
2
10
9.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps with 3 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions

100 C4H200 O C3H₁3Cl O C5H10N C6H14 C6H12 80 60 40 20 0 10 20 40 60 m/z 80 100 120 140 MassSpec9. Select the most reasonable formula for the molecule analyzed, based on the provided data (parent peak m/z at 84):
IR Spectrum (liquid film) 184 4000 100 80 60 40 20 40 13C NMR Spectrum (50.0 MHz, CDCI, solution) proton decoupled 200 ¹H NMR Spectrum (600 MHz, CDCI, solution) 1 10 9 8 3000 % of base peak 80 128 my 2000 V (cm¹) 119 M+* 134 120 160 m/e expansion 124 ppm 160 1600 I 7 200 I 6 120 ppm 1200 800 Mass Spectrum C10 H14 280 solvent 80 240 I 5 7.4 1 4 expansion 3 Problem 95 UV Spectrum max 262 nm (log10 € 2.5) solvent: ethanol -CH3 C 40 7.2 2 1 0 8 (ppm) TMS 1 I 1 0 8 (ppm) 201
Assign as many non-fingerprint region peaks as possible in anisole
What is the IR and HNMRAndCNMR and mass
Which C-H bonds are responsible for the following peaks/signals? C6H1202 s are Peak A = Peak B= Peak C= Enter 12 if a H is not labeled that created the peak/signal. this peak disappears with the addition of D20 By PPM
What is the mass of theis example explain
опанит 1715 1600 IR Spectrum 100 4000 (liquid film) 43 80 75 60 M 40 20 % of base peak 10 3000 40 C 13C NMR Spectrum (20.0 MHz, CDCI solution) proton decoupled 9 80 200 ¹H NMR Spectrum (100 MHz, CDCI, solution) 101 8 2000 v (cm¹) M** 132 120 160 m/e 160 7 6 1200 120 Mass Spectrum 200 240 280 800 C-H 5 C6H1203 solvent L 80 4 -CH3 No significant UV absorption above 220 nm 3 H-C-H u -CH3 40 2 59 TMS 0 1 8 (ppm) TMS 0 8 (ppm)
determine the possible molecular formula for this compund
100 80 60 20 % of base peak 30 40 80 V (cm¹) M**#103 120 160 m/e 200 Mass Spectrum C4H9NO₂ 240 280 21 No significa absorption ab
Find the Mass Spec
2. The reagent blank reading for a method to detect glucose gave the following fluorescence readings: 200, 215, 230, 222, and 212 RFU. Considering the calibration curve shown below, what is the limit of detection and limit of quantitation for this method? 6000 4000 2000 ¥=51 993x 119 63 50 100 Glucose ipmol) RFU (Ex/Em =535/587)