In a family-based genetic study for a mental disorder called marijuana dependence, a total of 50 families, each with a pair of siblings,were recruited. The result showed that 11 families have the 1st siblings with marijuana dependence and the 2nd siblings without thedisorder, while another 9 families are opposite (i.e. the 1st siblings without the disorder but the 2nd siblings with the disorder). Incontrast, 13 families have both siblings exhibiting the disorder and another 17 families have both siblings without the disorder. Whatkind of heritability can you calculate using this family study and what is the heritability value for marijuana dependence?O A. Broad-sense heritability, approximately 38%B. Narrow-sense heritability, approximately 38%O. Narrow-sense heritability, approximately 76%O D. Broad-sense heritability, approximately 76%

Marijuana is widely used throughout the world. It is seen that about 50–70% of the liability to…

Answered: In a family-based genetic study for a…

Human Anatomy & Physiology (11th Edition)

11th Edition

ISBN:9780134580999

Author:Elaine N. Marieb, Katja N. Hoehn

Publisher:Elaine N. Marieb, Katja N. Hoehn

Chapter1: The Human Body: An Orientation

Section: Chapter Questions

Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...

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Similar questions

Compare and contrast the molecular and phenotypic features of Prader-Willi and Angelman syndromes.
Type 1 albinism in humans is a rare hereditary condition associated with a reduced amount of active tyrosinase, an enzyme required for the conversion of the amino acid tyrosine to the dark pigment melanin. In the pedigree above, males are indicated by squares, females by circles and individuals with type 1 albinism are indicated by shading. Use A and a for the dominant (sufficient active tyrosinase) and recessive alleles (absent or insufficient tyrosinase activity), respectively. Remember that, when genotype is not known for a dominant phenotype, an m-dash is used (A– = AA or Aa). If individuals B and E marry, what is the probability that their first child will be affected by type 1 albinism? А. 1/2 В. 1/12 С. 1/4 D. 2/3 O E. 1/24
a geneticist has obtained 2 true-breeding strains of mice, each homozygous for an independently discovered recessive mutation that prevents the formationof hair on the body. one mutant strain is called naked, and the other is hairless. to determine whether the 2 mutations are alleles, the geneticist crosses naked and hairless mice with each other. All the offspring lack hair on their bodies. A: are naked and hairless mutations 2 different alleles? yes or no B: what type of experiment is this called
A made-up genetic phenotype in humans results in some people having both brown and blond body hair. It is noticeable only if you look closely and these individuals which have small. medium, and large patches of brown hair and small, medium, large patches of blond body hair spread throughout their body. a.) If this phenotype is only seen in females, males have completely blond or brown body hair, how would you describe the genetic nature of this phenotype?
Cystic fibrosis (CF) is an autosomal recessive trait. A three-generation pedigree is shown below for a family that carries the mutant allele for cystic fibrosis. Note that carriers are not colored in to allow you to figure out their genotypes. Normal allele = F CF mutant allele = f What is the genotype of individual #13? A) ff B) FF C) Ff D) it is impossible to tell
A woman diagnosed with early-onset Alzheimer's due to a mutation of the APP genehas children with a man that has no family history of familial Alzheimer's. Give the probability of each possible genotype with corresponding phenotype. (The woman has two possible allele combinations. You must show both possibilities)
In the previous topic, you learned that Gregor Mendel used Pisum sativum to conceptualize the governing laws of Genetics. In this activity, we will recall how Gregor Mendel utilized the idea of classical breeding to come up with desirable traits. Supposed you have two individual peas. One of the peas is a pure breed with round green seeds while the other has heterozygous round yellow seeds. Supposed a farmer wants to have pure breed peas that have green wrinkled seeds. How are you going to come up with these traits using the two peas that you have? (Note: If the F1 does not include a pure breed green wrinkled seed, you will use the F1 peas for next generation breeding and so on until you have the desired traits. Pure breed means homozygous alleles.) Show the Punnett squares for the cross. You will come up with two or more squares based on how many generations you made.
A woman who is heterozygous for gene B has brown eyes. B is a dominant allele for brown pigmentation, while b is recessive allele for blue pigmentation. The woman has a patch of blue color in her left eye. Give THREE (3) reasons how this might occur.
Below is a pedigree of a family with a history of Best disease (or vitelliform macular dystrophy). All members of this family underwent ASO testing using two different oligonucleotides (ASO 1 and ASO 2): one that hybridizes to the only known mutation that leads to Best disease and one that hybridizes to the wild-type gene sequence in the same region. From the information you have, how is Best disease most likely inherited? 1. II. III. 0 0 0 0 0 1 ? autosomal dominant autosomal recessive x-linked recessive x-linked dominant you cannot determine ASO 1 ASO 2 1-1 1-2 II-1 11-2 11-3
Within a mouse population, the black fur allele (B) is dominant to the white fur allele (b) and the short whisker allele (S) is dominant to the long-whisker allele (s). A heterozygous black-furred short-whiskered mouse is crossed with a homozygous white-furred long-whiskered mouse. What percentage of the offspring will be black-furred with long whiskers?
(a) Which allele/s will MOST likely result in an anomalous phenotype? (b) Explain your answer in (a). (c) Which allele/s will LEAST likely result in an anomalous phenotype? (d) One of the alleles code for a protein that tend to clump together. Which allele is it? (Hint: Recall what you learned from protein/amino acid structure.)
A worldwide survey of genetic variation in human populations reported the autosomal codominant MN blood group types in a sample of 1029 Chinese individuals from Hong Kong. The sample contained 342 people with blood type M, 500 with blood type MN, and 187 with blood type N. Part A The number of people expected in each blood-type category is: Enter the values expected for MM, MN and NN blood-type categories, respectively, separated by commas and using two decimal places (example 1.02, 2.30, 3.45).

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