Example: Electric Field and Potential Inside a Charged Sphere Problem: A sphere of radius R = 0.2 m is uniformly charged with a total charge Q = 5 μC. The sphere is made of a dielectric material with relative permittivity € = 4. Calculate: 1. The electric field intensity E(r) inside and outside the sphere. 2. The electric potential (r) at any point inside the sphere. Solution: Step 1: Given Data Radius of the sphere: R = 0.2m, Total charge: Q-5 μC=5× 10° C. Step 2: Electric Field Inside the Sphere (< Using Gauss's Law:
Example: Electric Field and Potential Inside a Charged Sphere Problem: A sphere of radius R = 0.2 m is uniformly charged with a total charge Q = 5 μC. The sphere is made of a dielectric material with relative permittivity € = 4. Calculate: 1. The electric field intensity E(r) inside and outside the sphere. 2. The electric potential (r) at any point inside the sphere. Solution: Step 1: Given Data Radius of the sphere: R = 0.2m, Total charge: Q-5 μC=5× 10° C. Step 2: Electric Field Inside the Sphere (< Using Gauss's Law:
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Transcribed Image Text:Example: Electric Field and Potential Inside a Charged Sphere
Problem: A sphere of radius R = 0.2 m is uniformly charged with a total charge Q = 5 μC. The sphere
is made of a dielectric material with relative permittivity € = 4. Calculate:
1. The electric field intensity E(r) inside and outside the sphere.
2. The electric potential (r) at any point inside the sphere.
Solution:
Step 1: Given Data
Radius of the sphere: R = 0.2m,
Total charge: Q-5 μC=5× 10° C.
Step 2: Electric Field Inside the Sphere (<
Using Gauss's Law:
<R)
Permittivity of free space: Co
8.854 × 10-12 F/m,
D.dA=qenclosed
A
•
Relative permittivity: €, = 4,
D= €E,
and enclosed p. V.
Permittivity of the dielectric:
=
c=coc, 8.854 x 10-12 x 43.54 × 10" F/m.
The charge density p is uniform, so:
Q
5 × 10-6
P
=
0.149 C/m³.
R³
(0.2)³
The enclosed charge at radius is:
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