Example two concentric annular rings are painted on a sheet of conducting paper with a highly conducting metal paint. The four radii are 1, 1.2. 3.5. and 3.7 cm. Connections made to the two rings show a resistance of 215 ohms between them. a) What is R, for the conducting paper? Using the two radii (1.2 and 3.5 cm) at which the rings are at their closest separation, we first evaluate the capacitance: = 5.19 x 10-11 F Σπέρν In(3.5/1.2) wherer is the unknown paper coating thickness. Now use 8.85 x 10-12 5.19 x 10-11at Thus C RC== o R, a Rs = of ⇒R = (51.9) (215) 8.85 = 215 b) If the conductivity of the material used as the surface of the paper is 2 S/m, what is the thickness of the coating? We use 1 2 x 1.26 x 10³ 1.26k/sq = 3.97 x 10 m = 0.397 mm

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Example
two concentric annular rings are painted on a sheet of conducting paper with a highly conducting metal
paint. The four radii are 1, 1.2, 3.5. and 3.7 cm. Connections made to the two rings show a resistance
of 215 ohms between them.
a) What is R, for the conducting paper? Using the two radii (1.2 and 3.5 cm) at which the rings are
at their closest separation, we first evaluate the capacitance:
= 5.19 x 10-11 F
27601
C =
In (3.5/1.2)
where is the unknown paper coating thickness. Now use
8.85 x 10-12
5.19 x 10-1101
Thus
RC =
1=
σ R₁
€0
O
⇒R=
1
Rs = =
of
=
1.26k2/sq
b) If the conductivity of the material used as the surface of the paper is 2 S/m, what is the thickness
of the coating? We use
(51.9) (215)
8.85
1
2 x 1.26 x 10³
<= 215
=
= 3.97 x 10 m = 0.397 mm
Transcribed Image Text:Example two concentric annular rings are painted on a sheet of conducting paper with a highly conducting metal paint. The four radii are 1, 1.2, 3.5. and 3.7 cm. Connections made to the two rings show a resistance of 215 ohms between them. a) What is R, for the conducting paper? Using the two radii (1.2 and 3.5 cm) at which the rings are at their closest separation, we first evaluate the capacitance: = 5.19 x 10-11 F 27601 C = In (3.5/1.2) where is the unknown paper coating thickness. Now use 8.85 x 10-12 5.19 x 10-1101 Thus RC = 1= σ R₁ €0 O ⇒R= 1 Rs = = of = 1.26k2/sq b) If the conductivity of the material used as the surface of the paper is 2 S/m, what is the thickness of the coating? We use (51.9) (215) 8.85 1 2 x 1.26 x 10³ <= 215 = = 3.97 x 10 m = 0.397 mm
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