ет а a. What is the sinusoidal expression for the current, i(t), through this capacitor ? ii(t) Xcl Vin = 30 sin (wt) Vin C 102 V=C 2/2 V = c +/- & i(t) = Sin (wt +90°) | Ipl = /Vp Хо (૭ 30/ 3A i(t) = 3 sin (wt +90°) A Sketch v(t) and i(t) sinusoidal wave from s on the same axis. V(wt), i (wt) 30 V(t) = 30 sin (wt) i(t) = 3sin(wt +90°) 3 A K -90° 90° 1802 270° wt 0 360

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter2: Fundamentals
Section: Chapter Questions
Problem 2.7P: Let a 100V sinusoidal source be connected to a series combination of a 3 resistor, an 8 inductor,...
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The voltage across a 10 Ω capacitive reactance is:   v(t) = 30 sin ῳt.

  1. What is the sinusoidal expression for the current, i(t), through the capacitor.
  2. Sketch v(t) and i(t) sinusoidal waveforms on the same axis

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ет
а
a.
What is the sinusoidal expression for
the current, i(t), through this capacitor ?
ii(t)
Xcl
Vin = 30 sin (wt)
Vin
C
102
V=C
2/2
V = c +/- & i(t) = Sin (wt +90°)
| Ipl = /Vp
Хо
(૭
30/
3A i(t) = 3 sin (wt +90°) A
Sketch v(t) and i(t) sinusoidal wave from s
on the same axis.
V(wt), i (wt)
30
V(t) = 30 sin (wt)
i(t) = 3sin(wt +90°)
3
A
K
-90°
90°
1802
270°
wt
0
360
Transcribed Image Text:ет а a. What is the sinusoidal expression for the current, i(t), through this capacitor ? ii(t) Xcl Vin = 30 sin (wt) Vin C 102 V=C 2/2 V = c +/- & i(t) = Sin (wt +90°) | Ipl = /Vp Хо (૭ 30/ 3A i(t) = 3 sin (wt +90°) A Sketch v(t) and i(t) sinusoidal wave from s on the same axis. V(wt), i (wt) 30 V(t) = 30 sin (wt) i(t) = 3sin(wt +90°) 3 A K -90° 90° 1802 270° wt 0 360
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