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Here, you will use complex exponentials to express the composite EEG signal in Problem 2 as a single sinusoidal function: y(t) = 3 sin(400лt +л/6) + 2 cos(400лt - л/4) To do this, use the following: Y₁(t) = A₁ sin(wt + 0₁) = A₁ cos(wt + 0₁ − π/2) = Re(A₁ej(wt+0₁−π/2)) - y2(t) = A2 cos(wt + 0₂) = A₂ cos(wt + 0₂) = Re(A₂ej (@t+0₂)) Then, add the two signals using phasor notation, and convert it back to a single cosine function (i.e. y(t) = A3 cos(wt + 03)).

Here, you will use complex exponentials to express the composite EEG signal in Problem 2 as a single sinusoidal function: y(t) = 3 sin(400лt +л/6) + 2 cos(400лt - л/4) To do this, use the following: Y₁(t) = A₁ sin(wt + 0₁) = A₁ cos(wt + 0₁ − π/2) = Re(A₁ej(wt+0₁−π/2)) - y2(t) = A2 cos(wt + 0₂) = A₂ cos(wt + 0₂) = Re(A₂ej (@t+0₂)) Then, add the two signals using phasor notation, and convert it back to a single cosine function (i.e. y(t) = A3 cos(wt + 03)).

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Here, you will use complex exponentials to express the composite EEG signal in Problem 2 as a single sinusoidal function: y(t) = 3 sin(400лt +л/6) + 2 cos(400лt - л/4) To do this, use the following: Y₁(t) = A₁ sin(wt + 0₁) = A₁ cos(wt + 0₁ − π/2) = Re(A₁ej(wt+0₁−π/2)) - y2(t) = A2 cos(wt + 0₂) = A₂ cos(wt + 0₂) = Re(A₂ej (@t+0₂)) Then, add the two signals using phasor notation, and convert it back to a single cosine function (i.e. y(t) = A3 cos(wt + 03)).
Transcribed Image Text:Here, you will use complex exponentials to express the composite EEG signal in Problem 2 as a single sinusoidal function: y(t) = 3 sin(400лt +л/6) + 2 cos(400лt - л/4) To do this, use the following: Y₁(t) = A₁ sin(wt + 0₁) = A₁ cos(wt + 0₁ − π/2) = Re(A₁ej(wt+0₁−π/2)) - y2(t) = A2 cos(wt + 0₂) = A₂ cos(wt + 0₂) = Re(A₂ej (@t+0₂)) Then, add the two signals using phasor notation, and convert it back to a single cosine function (i.e. y(t) = A3 cos(wt + 03)).
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