Question 10 30 V 2 ΜΩ w t=0 1 ΜΩ + 2 μF Vc(t) "For the circuit shown, determine the initial value of the voltage, vC (t)." Answer: Answer
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
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- Hello, Can someone help check these answers assuming that the circuit is closed instead of open? Thank you3. An electrical device shown below has the following depicted voltage and current definition. The current in and the voltage vin for a certain period is recorded as shown in the bottom picture. (1) In different periods from 0 to time T4, determine if the electrical device works as a load or a source. iin + iin Vin Electrical Device 0 T₁ T2 T3 ΤΑ t Vin T2 ΤΑ t= Using Kirchhoff's rules, find the following. (₁ = 70.9 V, 8₂= 60.7 V, and 83 1 E₁ R₂ E₂ 4.00 ΚΩ www R₂ 3.00 ΚΩ d E₁ 2.00 ΚΩ www R₁ (a) the current in each resistor shown in the figure above (b) the potential difference between points c and f 79.1 V.)
- How do I calculate this circuits values?I keep on getting 1.6 W and -1.6 W for this problem but that keeps on being wrong I am pretty sure my error is in nomenclature but I am running out of gussesWhat is the value of Rin ohms such that the current through the 25 ohm resistance is zero amperes. 100 45 0 25 Q 100 V RO 20 Q Type your numencarswen pnc sumN 7:52 Et C S/10/2 99+ +
- What is the total current? + 497 V R4 ko C +0.04 µF L 8 4H 750 Hz O A. 56.6 mA O B. 141 mA O C. 191 mA O D. 244 mAI am a bit confused on how to get the missing values.C -Q (A) 0.25 uF 10V 2uF 4uF (B) Figure 3: 3. In Figure 3 the capacitors were discharged before being connected to the battery. (a) In Figure 3A the net positive charge delivered by the battery is +Q1 to C1 and a net negative charge -[Q2 + Q3] is delivered to C2 and C3 [-Q2 is delivered to C2 and -Q3 to C3]. From conservation of charge[net charge is zero since both the battery and the capacitors have a zero net excess charge] and path independence of the electric field[sum of voltages must add up to zero for a closed path or conservation of energy]: Q1 + (-Q2) + (-Q3) = 0 conservation of charge +%-왕-용 (True, False) = 0 conservation of energy +V - = 0 conservation of energy (b) If (a) is true then the charge Q1, Q2 and Q3 follow from above three equations as C1(C2 + C3) V Q2 = Ci + C2 + C3 C1 C3 Ci + C2 + C3 Q1 = Q3 = V, (True, False) C1 + C2 + C3 (c) In Figure 3A the net positive charge delivered by the battery is Qtot = Q1 = C1(C2+C3) v which implies an equivalent capacitance of Qtot…
- Q2 Please respond to question in attached image. Thank you.Subject to a step input, the voltage drop across the resistor took 696.3103us to reach 13% of its steady value from rest. Determine the time (ms) needed to reach 90% of its steady value from 10% Determine the time (ms) needed to reach 80% of its steady value from 20%Question 2 4 for > 0 as shown in Figure 1 below. What is the energy? The independent current source in the circuit generates zero current for < 0 and a pulse of O a. g0r e Ob.30 e 20ke 2_-10t b.20,-10 c. 90re J 2--10t
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