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(A) 0.25 uF 10V 2uF 4uF (B) Figure 3: 3. In Figure 3 the capacitors were discharged before being connected to the battery. (a) In Figure 3A the net positive charge delivered by the battery is +Q1 to Cj and a net negative charge -[Q2 + Q3] is delivered to C2 and C3 (-Q2 is delivered to C2 and -Q3 to C3]. From conservation of charge(net charge is zero since both the battery and the capacitors have a zero net excess charge] and path independence of the electric field[sum of voltages must add up to zero for a closed path or conservation of energy): Q1 + (-Q2) + (-Q3) = 0 conservation of charge +%-용-용 +V, - 4 - conservation of energy (True, False) = 0 conservation of energy (b) If (a) is true then the charge Q1, Q2 and Qa follow from above three equations as C1(C2 + C3) C,C2 Q2 = Ci + C2 + C3 C\C3 Q3 = C1 + C2 + C3 Q1 = V, (True, False) Ci + C2 + C3 (c) In Figure 3A the net positive charge delivered by the battery is Qtot = Q1 = CatCal V, which implies an equivalent capacitance of Stot = V C(C2+Ca) Ci+C2+Cg (True,False) CuCatC ) HE

(A) 0.25 uF 10V 2uF 4uF (B) Figure 3: 3. In Figure 3 the capacitors were discharged before being connected to the battery. (a) In Figure 3A the net positive charge delivered by the battery is +Q1 to Cj and a net negative charge -[Q2 + Q3] is delivered to C2 and C3 (-Q2 is delivered to C2 and -Q3 to C3]. From conservation of charge(net charge is zero since both the battery and the capacitors have a zero net excess charge] and path independence of the electric field[sum of voltages must add up to zero for a closed path or conservation of energy): Q1 + (-Q2) + (-Q3) = 0 conservation of charge +%-용-용 +V, - 4 - conservation of energy (True, False) = 0 conservation of energy (b) If (a) is true then the charge Q1, Q2 and Qa follow from above three equations as C1(C2 + C3) C,C2 Q2 = Ci + C2 + C3 C\C3 Q3 = C1 + C2 + C3 Q1 = V, (True, False) Ci + C2 + C3 (c) In Figure 3A the net positive charge delivered by the battery is Qtot = Q1 = CatCal V, which implies an equivalent capacitance of Stot = V C(C2+Ca) Ci+C2+Cg (True,False) CuCatC ) HE

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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C -Q (A) 0.25 uF 10V 2uF 4uF (B) Figure 3: 3. In Figure 3 the capacitors were discharged before being connected to the battery. (a) In Figure 3A the net positive charge delivered by the battery is +Q1 to C1 and a net negative charge -[Q2 + Q3] is delivered to C2 and C3 [-Q2 is delivered to C2 and -Q3 to C3]. From conservation of charge[net charge is zero since both the battery and the capacitors have a zero net excess charge] and path independence of the electric field[sum of voltages must add up to zero for a closed path or conservation of energy]: Q1 + (-Q2) + (-Q3) = 0 conservation of charge +%-왕-용 (True, False) = 0 conservation of energy +V - = 0 conservation of energy (b) If (a) is true then the charge Q1, Q2 and Q3 follow from above three equations as C1(C2 + C3) V Q2 = Ci + C2 + C3 C1 C3 Ci + C2 + C3 Q1 = Q3 = V, (True, False) C1 + C2 + C3 (c) In Figure 3A the net positive charge delivered by the battery is Qtot = Q1 = C1(C2+C3) v which implies an equivalent capacitance of Qtot = CC2+Ca) (True,False) +C2+C (d) The total energy delivered by the battery is Etot = V,Qtot = T+ V and the total energy stored in the three capacitors is 요+ + - 융 ve. (True, False) = 1+C2+C3 (e) In Figure 3B the equivalent capacitance is 0.24 uF and the net positive charge delivered by the battery is 2.4µC the energy delivered by the battery is 24µJ while the energy stored in the capacitors is 124J (True,False)
Transcribed Image Text:C -Q (A) 0.25 uF 10V 2uF 4uF (B) Figure 3: 3. In Figure 3 the capacitors were discharged before being connected to the battery. (a) In Figure 3A the net positive charge delivered by the battery is +Q1 to C1 and a net negative charge -[Q2 + Q3] is delivered to C2 and C3 [-Q2 is delivered to C2 and -Q3 to C3]. From conservation of charge[net charge is zero since both the battery and the capacitors have a zero net excess charge] and path independence of the electric field[sum of voltages must add up to zero for a closed path or conservation of energy]: Q1 + (-Q2) + (-Q3) = 0 conservation of charge +%-왕-용 (True, False) = 0 conservation of energy +V - = 0 conservation of energy (b) If (a) is true then the charge Q1, Q2 and Q3 follow from above three equations as C1(C2 + C3) V Q2 = Ci + C2 + C3 C1 C3 Ci + C2 + C3 Q1 = Q3 = V, (True, False) C1 + C2 + C3 (c) In Figure 3A the net positive charge delivered by the battery is Qtot = Q1 = C1(C2+C3) v which implies an equivalent capacitance of Qtot = CC2+Ca) (True,False) +C2+C (d) The total energy delivered by the battery is Etot = V,Qtot = T+ V and the total energy stored in the three capacitors is 요+ + - 융 ve. (True, False) = 1+C2+C3 (e) In Figure 3B the equivalent capacitance is 0.24 uF and the net positive charge delivered by the battery is 2.4µC the energy delivered by the battery is 24µJ while the energy stored in the capacitors is 124J (True,False)
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