2. The source in the following figure (Fig. 12.33b) has the frequency range shown. Calculate the range of Q for the circuit, assuming the capacitor has a dielectric resistance of 200 MQ. Vs f=60 Hz to 3 kHz 0.22 uF
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- R 1. Measure the internal resistance of the 1mH inductor. Set up the given circuit with R = 270n and L = 1mH. Apply a sinusoidal voltage as input. Adjust V, = 4Vpp and set the frequency as 20kHz. Observe the input voltage and the V, L voltage across the inductor simultaneously using an ocilloscope and plot both signals. Find the phase difference between these signals and comment on the results.q11Best choice
- 10 V sine 90 kHz 1 kQ C1 1 nF 2. Using a Square function with 90,000 Hz in your function-generator, a 1000-ohm resistor, and a 1 nano-Farad capacitor, determine the charging time for the capacitor. Show your calculations and show the charging-discharge curve with an oscilloscope in TINKERCAD.An AC source has an output rms voltage of 78V at a frequency of 80Hz. If the source is connected across a 25mH inductor, what is the rms current in the circuitDraw the osciloprams for ult) ond ick] Problem For the following pairs of voltages and currents, indicate whether the element involved is a capacitor, an inductor, or a resistor, and the value of C, L or R if sufficient data are given: u = 550 sin( 377t + 50°) i= 11 sin( 377t - 40°) a) u = 36 sin( 754t +80°) i= 4 sin( 754t+170°) b)
- R=1 ka A Oscilloscope V-5 V f=500 Hz In the given circuit, a sinusoidal signal is applied at the source, current measured by AVO meter is 0.01A (RMS) and voltage measured by oscilloscope is 25mV(peak). What is the capacitance value of capacitor? Lütfen birini seçin: a.1 uF b.0.18 mF c.0.15 mF d.0.1mF e.0.12 mFConsider the sinusoidal voltage and current for an inductor. If you are given the phase angle of the voltage, the phase angle of the current will be:a) The same as the voltage phase angleb) 90°more than the voltage phase anglec) 90° less than the voltage phase angled) Dependent on the inductanceAn AC circuit is composed of a serial connection of: a resistor with resistance 50 0, a coil with inductance 0.3 H and a capacitor with capacitance 15 µF. The circuit is connected to an AC voltage source with amplitude 25 V and frequency 50 Hz. Determine the amplitude of the electric current in the circuit and a phase difference between the voltage and the current. R=50 2 C=15 µF omH L=0.3 H U.-25 V f=50 Hz Hi guys! Here is something you can practice with. Simplify the circuit above. The final answer is RLC circuit the amplitude of the current is approximate: /m = 0.2 A. %3D The phase difference between the voltage and the current is about: p = -67°. %3D